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Umnica [9.8K]
3 years ago
9

Please answer the following question in the picture answer the question

Chemistry
2 answers:
raketka [301]3 years ago
6 0
I think the answer is warm and high salinity
KATRIN_1 [288]3 years ago
3 0

Answer:

Cold and High Salinty

Explanation:

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Draw a structural formula of the sr configuration of the compound shown below.
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What are the properties of coins?
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In the lewis structure of ch3oh, how many bonding pairs of electrons are there?
zysi [14]
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Explanation:
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8 0
4 years ago
The combustion of methane(CH4) produces carbon dioxide and water. Assume that 2.0 mol of CH4 burned in the presence of excess ai
harkovskaia [24]

Answer:

The answer to your question is 98.9 %

Explanation:

Data

moles of methane = CH₄ = 2.0

excess air

Percent yield = ?

mass of CO₂ = 87 g

- Balanced chemical reaction

                CH₄  +  2O₂   ⇒  CO₂  +  2H₂O

      Reactants     Elements       Products

             1                    C                   1

             4                   H                   2

             4                   O                   2

- Calculate the molar mass of CH₄

CH₄ = 12 + 4 = 16 g

- Convert the moles to mass

                     16 g of CH₄ ----------------- 1 mol

                       x                -----------------  2 moles

                       x = (2 x 16) / 1

                       x = 32 g of CH₄

-Calculate the theoretical formation of CO₂

                     16 g of CH₄ ----------------- 44 g of CO₂

                     32 g of CH₄ ----------------  x

                            x = (32 x 44) / 16

                            x = 88 g of CO₂

-Calculate the Percent yield

     Percent yield = Actual yield/Theoretical yield x 100

     Percent yield = 87/88 x 100

    Percent yield = 98.9 %

3 0
3 years ago
Balance this equation. if a coefficient of "1" is required, choose "blank" for that box.
blondinia [14]
Step 1: Write Imbalance Equation

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                             CH₃CHO  +  O₂    →    2 CO₂  +  H₂O 

Step 3: Balance Hydrogen Atoms:
                                                      There are 4 hydrogen atoms at reactant side and 2 Hydrogen atoms at product side. So, multiply H₂O by 2 to balance Hydrogen on both sides. i.e.

                    CH₃CHO  +  O₂    →    2 CO₂  +  2 H₂O

Step 4: Balance Oxygen Atoms:
                                                   There are 3 Oxygen atoms at reactant side and 6 Oxygen atoms at product side. In order to balance them multiply O₂ on reactant side by 2.5 (5/2). i.e  

                    CH₃CHO  +  5/2 O₂    →    2 CO₂  +  2 H₂O

Step 6: Eliminate Fraction:
                                         Multiply overall equation by 2 to eliminate fraction. i.e. 

                    2 CH₃CHO  +  5 O₂    →    4 CO₂  +  4 H₂O
7 0
3 years ago
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