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<span>Brass, which is made by melting copper and zinc together, is harder, stronger, morecorrosion resistant and has an attractive gold colour. It still keeps its anti-bacterial properties, which makes it a great material for door knobs, handrails and plumbing fittings. Copper has been used to make coins for centuries.</span>
Answer: There are
five <span>bonding pairs of electrons in Methanol.
Explanation: Those electron pairs which are being shared between two atoms in molecule are called as
bonding pair electrons. While, those electron pairs which are not involved in bond formation and are not shared between two atoms are called as
Non-Bonding electron pairs.
In molecule of
Methanol as shown below, it can be seen that carbon atom is forming four bonds with three hydrogen atoms and one oxygen atom by sharing four electron pairs and oxygen is forming two bonds, one with carbon atom and one with hydrogen atom. There are two lone pair of electrons present on oxygen atom which are not taking part in and formation.</span>
Answer:
The answer to your question is 98.9 %
Explanation:
Data
moles of methane = CH₄ = 2.0
excess air
Percent yield = ?
mass of CO₂ = 87 g
- Balanced chemical reaction
CH₄ + 2O₂ ⇒ CO₂ + 2H₂O
Reactants Elements Products
1 C 1
4 H 2
4 O 2
- Calculate the molar mass of CH₄
CH₄ = 12 + 4 = 16 g
- Convert the moles to mass
16 g of CH₄ ----------------- 1 mol
x ----------------- 2 moles
x = (2 x 16) / 1
x = 32 g of CH₄
-Calculate the theoretical formation of CO₂
16 g of CH₄ ----------------- 44 g of CO₂
32 g of CH₄ ---------------- x
x = (32 x 44) / 16
x = 88 g of CO₂
-Calculate the Percent yield
Percent yield = Actual yield/Theoretical yield x 100
Percent yield = 87/88 x 100
Percent yield = 98.9 %
Step 1: Write Imbalance Equation
CH₃CHO + O₂ → CO₂ + H₂O
Step 2: Balance Carbon Atoms:
There are 2 carbon atoms at reactant side and one at product side. So multiply CO₂ with 2 to balance them. i.e.
CH₃CHO + O₂ → 2 CO₂ + H₂O
Step 3: Balance Hydrogen Atoms:
There are 4 hydrogen atoms at reactant side and 2 Hydrogen atoms at product side. So, multiply H₂O by 2 to balance Hydrogen on both sides. i.e.
CH₃CHO + O₂ → 2 CO₂ + 2 H₂O
Step 4: Balance Oxygen Atoms:
There are 3 Oxygen atoms at reactant side and 6 Oxygen atoms at product side. In order to balance them multiply O₂ on reactant side by 2.5 (5/2). i.e
CH₃CHO + 5/2 O₂ → 2 CO₂ + 2 H₂O
Step 6: Eliminate Fraction:
Multiply overall equation by 2 to eliminate fraction. i.e.
2 CH₃CHO + 5 O₂ → 4 CO₂ + 4 H₂O