Answer:
a) cu2+ + 1Hg (l) 1Cl- equilibrium cu (s) + Hg2Cl2 (s)
b) 0.068 V.
Explanation:
A) Cu2+ + 2e- euilibrium cu (s)
Hg2Cl2 + 2e- equilibrium 2Hg (l) + 1cl-
Cell Reaction: cu2+ + 1Hg (l) 1Cl- equilibrium cu (s) + Hg2Cl2 (s)
B) To calculate the cell voltage
E = E_o Cu2+/Cu - (0.05916 V / 2) log 1/Cu2+
putting values we get
= 0.339V + (90.05916V/2)log(0.100) = 0.309V
E_cell = E Cu2+/Cu - E SCE = 0.309 V - 0.241 V = 0.068V.
The formula of hydrated copper(II) sulfate is CuSO4.10H2O
<h3>What is the formula of the hydrated copper (ii) sulfate salt?</h3>
The formula of the hydrated copper (ii) sulfate is determined as follows:
Mass of hydrated salt = 12.5 g
Mass of anhydrous salt = 8.0 g
Mass of water = 12.5 - 8 = 4.5 g
mole ratio of water and anhydrous salt is;
4.5/18 : 8.0/159.5
0.562 : 0.05
10 : 1
Water of crystallization (n) = 10.
Therefore, the formula of hydrated copper(II) sulfate is CuSO4.10H2O
Learn more about water of crystallization at: brainly.com/question/26146814
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Answer:
maybe 1 or 3 im not sure
Explanation:
i didn't study it yet sorry for not helping but try asking someone else
Because the amount of hydrogens all depends on the valence electrons
