There must be two binomial factors. Thus, we eliminate Answer A, which contains only one such factor.
(x-3)(x+3) has the form (a-b)(a+b), which equals a^2 - 3^2. This is a special product. Eliminate Answer B, because a^2 - 3^2 does not equal x^2 - 6x + 9.
The middle term of x^2 - 6x + 9 is negative. This quadratic has the form x^2 - y^2, which is special product and whose factors are (x-y) and (x-y).
Thus, x^2-6x+9 = (x-3)(x-3) (Answer C)
Answer:
a. 23.02 %
b. 49%
c. W
Step-by-step explanation:
Solution:-
- A multi-variable function for the percentage of fish in the lake that are intolerant to the pollution is given as:

Where,
W: percentage of wetland
R: percentage of residential area
A: percentage of agriculture
- We are to evaluate the percentage of fish intolerant to pollution in the case where W = 3 , R = 15 , A = 0. We will plug in the values in the modeled function P ( W , R , A ) as follows:

- To determine the maximum percentage of fish that will be intolerant to pollution we will employ the use of critical points. The critical point that is defined by the linear relationship between P and all other parameters ( W, R , A ). The maximum value occurs when W = R = A = 0.

- Hence, the maximum value of the function is 49%.
- The linear relationship between each induvidual parameter ( R, W , A ) and the function ( P ) is proportional in influence. The extent of influence can be quantized by the constant multiplied by each parameter.
- We see that that ( 1.61*W ) > ( 1.41R ) > ( 1.38A ). The greatest influence is by parameter ( W ) i.e the influence of percentage of wetlands .
Assuming that the x is not part of the ^-1 the range would be
[0,π/2) U (π/2,<span>π]</span>
Answer:
option D is correct
Step-by-step explanation:
is it correct
The slope
m = (y2 - y1)/(x2 - x1)
m = ( 38 - -2)/ (-29 - -64)
m = 40/35
simplify
m = 8/7
Hope this helps