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3 years ago

8

A box of 120 crayons contains variations of three colors: blue, red, and purple. The ratio of blue crayons to red crayons is 11:

2, and the ratio of the number of red crayons to purple crayons is 2:7. If all of the purple crayons were removed, how many crayons would be left in the box?
E. 16
F. 42
G. 78
H. 113

2 answers:

Kaylis [27]3 years ago

4 0

113 I’m pretty sure or 78 so H or G

Luden [163]3 years ago

3 0

I think it’s should be H

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2. option D

3. option C

4. option D

5. option C

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<h2> $1. \: \sqrt{ - 9}$ </h2>

$\sqrt{ - 1(9)}$

$\sqrt{ - 1} \times \sqrt{ 9}$

$i \times \sqrt{9}$

$i \times \sqrt{ {3}^{2} }$

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<h2> $2. \: \sqrt{ - 8}$ </h2>

$\sqrt{ - 1(8)}$

$\sqrt{ - 1} \times \sqrt{8}$

$i \times \sqrt{8}$

$i \times \sqrt{ {2}^{2} \times 2 }$

$2i \sqrt{2}$

<h2> $3. \: \sqrt{ - 80}$ </h2>

$\sqrt{ - 1} \times \sqrt{80}$

$i \times \sqrt{80}$

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<h2> $4. \: \sqrt{ - 75}$ </h2>

$\sqrt{ - 1} \times \sqrt{75}$

$i \times \sqrt{75}$

$i \times \sqrt{ {5}^{2} \times 3 }$

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<h2> $5. \: \sqrt{ - 72}$ </h2>

$\sqrt{ - 1} \times \sqrt{72}$

$i \times \sqrt{72}$

$i \times ( {6}^{2} \times 2)$

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<h2> $6. \sqrt{ - 20}$ </h2>

$\sqrt{ - 1} \times \sqrt{20}$

$i \times \sqrt{20}$

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<h2> $7. \: \sqrt{ - 27}$ </h2>

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$i \times \sqrt{ {3}^{2} \times 3}$

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<h2> $8. \: \sqrt{ - 12}$ </h2>

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<h2> $9. \: \sqrt{ - 125}$ </h2>

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<h2> $10. \: \sqrt{ - 180}$ </h2>

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$6i \sqrt{5}$

<h3>Hope it is helpful...</h3>

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