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qaws [65]
3 years ago
14

What is 27/70 as a decimal​

Mathematics
2 answers:
Ivahew [28]3 years ago
3 0

Answer:

0.385 is your answer. :)

DENIUS [597]3 years ago
3 0

Answer:

0.39

Step-by-step explanation:

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Write an equation in slope-intercept form of the line that passes through (-5, 19) and (5.13).
ruslelena [56]

Answer:

y=-3/5x+16

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(13-19)/(5-(-5))

m=-6/(5+5)

m=-6/10

simplify

m=-3/5

y-y1=m(x-x1)

y-19=-3/5(x-(-5))

y-19=-3/5(x+5)

y=-3/5x-15/5+19

y=-3/5x-3+19

y=-3/5x+16

3 0
3 years ago
Kimora’s cell phone company charges her $35 a month for phone service plus $.05 for each text message sent. How many text messag
professor190 [17]

Given that Kimora’s cell phone company charges her $35 a month for phone service plus $.05 for each text message sent.

Kimora's cell phone bill for one month is $52.

We need to determine the number of text messages Kimora sent for one month.

Also, we need to write and equation and solve it.

<u>The equation:</u>

Let x denote the number of text messages Kimora sent for one month.

Thus, the equation is given by

35+0.05x=52

Therefore, the equation for the number of text messages Kimora sent for one month is 35+0.05x=52

<u>Solving the equation:</u>

We need to solve the equation 35+0.05x=52

Subtracting both sides of the equation by 35, we get;

0.05x=17

Dividing both sides of the equation by 0.05, we get;

x=340

Therefore, the number of messages sent is 340.

3 0
3 years ago
Evaluate the function when x=−2, 0, and 5. g(x)=3x−2
kipiarov [429]
I hope this helps....

x=-2
g(-2)= 3(-2)-2
= -6-2
g(-2)= -8

x=0
g(0)= 3(0)-2
=-2

x=5
g(5)=3(5)-2
g(5)=13
5 0
3 years ago
Read 2 more answers
Simplify the sum. d^2-9d+20/d^2-3d-10 plus d^2-2d-8/d^2+4d-32
dimaraw [331]
For this case what you should do is follow the following steps:
 1) factorize numerator and denominator of both expressions.
 2) cancel similar terms
 3) add both fractions by cross product
 4) Rewrite the numerator and denominator.
 Answer:
 
See attached image.

3 0
4 years ago
Read 2 more answers
I have no idea where to start on either of these problems. Would someone explain the steps to me? My teacher hasn’t gone over th
bazaltina [42]

Answer:

Problem 9:  -1/2

Problem 10:  1/5

Step-by-step explanation:

Problem 10:  Label the given ln e^(1/5) as y = ln e^(1/5).

Write the identity e = e.  Raise the first e to the power y and the second e to the power 1/5 (note that ln e^(1/5) = 1/5).  Thus, we have:

e^y = e^(1/5), so that y = 1/5 (answer).


Problem 9:    Let y = (log to the base 4 of) ∛1 / ∛8, or

                            y = (log to the base 4 of) ∛1 / ∛8, or

                             y = (log to the base 4 of) 1 /2

Write out the obvious:              

                            4                                   =   4

Raise the first 4 to the power y and raise the second 4 to the power (log to the base 4 of) 1 /2.  This results in:

                              4^y    =     1/2.  Solve this for y.  

                                 Note that 4^(1/2) = 2, so that 4^(-1/2) = 1/2

Thus, y = -1/2

                   


3 0
3 years ago
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