Answer:
W' = 54.4 pounds
Step-by-step explanation:
Given that,
The weight of a bag of books = 40 pounds
After picking up some books at school, the weight has increased by 36%.
We need to find the weight of the bag now. Let the new weight is W'.
So,
W' = 40 +36% of 40
i.e.

So, the new weight of the bag is equal to 54.4 pounds.
Whether an object will sink or float depends on how the buoyant force compares with the object`s weight. This, in turn, depends on the object`s density.
Answer: B ) The objects probably have different densities.
That's the answer
-You have to multiply each side by 2
-And then move the constant to the right
And then calculate
26-18=x
X=-8
Answer:
Dimensions will be
Length = 7.23 cm
Width = 7.23 cm
Height = 9.64 cm
Step-by-step explanation:
A closed box has length = l cm
width of the box = w cm
height of the box = h cm
Volume of the rectangular box = lwh
504 = lwh

Sides which involve length and width and height, cost = 3 cents per cm²
Top and bottom of the box costs = 4 cents per cm²
Cost of the sides
= 3[2(l + w)h] = 6(l + w)h
= 3[2(l + w)h]

Cost of the top and the bottom
= 4(2lw) = 8lw
Total cost of the box C =
+ 8lw
=
+ 8lw
To minimize the cost of the sides


---------(1)


-------(2)
Now place the value of w from equation (1) to equation (2)


l³ = 378
l = ∛378 = 7.23 cm
From equation (2)


w = 7.23 cm
As lwh = 504 cm³
(7.23)²h = 504

h = 9.64 cm
Redued by 15%
orignal=100%
decrease by 15%=100%-15%=85%
find 85% of original
orignal=15 feet
85% of 15=0.85 times 15=12.75 feet
answer is B