Let f(x) = sin x; Sketch the graph of f^2
1 answer:
Answer: see graph
<u>Step-by-step explanation:</u>
Look at the Unit Circle to see the coordinates of the quadrangles.
Build a sine table for one period (0° - 360°).
<u> x </u> <u> y = sin(x) </u> <u> y² = (sin(x))² </u> <u> (x, y²) </u>
0° sin(0°) = 0 (0)² = 0 (0°, 0)
90° sin(90°) = 1 (1)² = 1 (90°, 1)
180° sin(180°) = 0 (0)² = 0 (180°, 0)
270° sin(270°) = -1 (-1)² = 1 (270°, 1)
360° sin(360°) = 0 (0)² = 0 (360°, 0)
Now plot the (x, y²) coordinates on your graph.
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Answer:
Solution → (2, -1)
Step-by-step explanation:
Input-output values table for equation (1),
2x + y = 3
x -1 0 1 2
y 5 3 1 -1
Input-output values table for equation (2),
y = x - 3
x -1 0 1 2
y -4 -3 -2 -1
Now plot these points to get the graphs of both the equations.
Common point (2, -1) of both the lines will be the solution of the system of equations.
