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Llana [10]
3 years ago
10

I need help please and thank you

Mathematics
1 answer:
Andreyy893 years ago
7 0
Go download Conects :)
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Check here for instructional material to complete this problem.
NARA [144]

Answer:

makes no sense

Step-by-step explanation:

6 0
2 years ago
It tales 1/2 of a box of nails to build a bird house. if hoy walter to build 5 bird houses, how many boxes would you need
Vika [28.1K]
1/2 * 5 = 2.5.
You would need 2.5 boxes to build 5 birdhouses.
4 0
3 years ago
What is the approximate value of x in the diagram below? (Hint: You will need
Delicious77 [7]

Answer:

B. 39.59

Step-by-step explanation:

So 43 degrees, you know the length of the opposite side (27) and the angle (43 degrees), the only unknown is the hypotenuse. So you're looking for a trigonometric ratio that uses the angle (all of them do, except technically the inverse don't), the opposite side, and the hypotenuse. Sine is defined as \frac{opposite}{hypotenuse}. So let's plug in known values:

sin(43) = \frac{27}{x}

Multiply both sides by x

sin(43) * x = 27

divide both sides by sin(43)

x=\frac{27}{sin(43)}

Normally I would use a calculator, but in this case I'll use the approximation given in the problem of 0.682

x=\frac{27}{0.682}

simplify the fraction

x\approx39.59

8 0
2 years ago
What is the solution of the system of equations that contains the equation - 3x - 9y = 18 and the equation of the line shown on
Diano4ka-milaya [45]

Answer:

No solution

Step-by-step explanation:

7 0
3 years ago
How many different 5-person subcommittees can be formed from a club having 12 members
Wittaler [7]
Given that there are 12 persons, the first choice may be in 12 different ways, the second choice may be in 11 different ways, ther third in 10 different ways, the fourth in 9 different ways and the fith in 8 different ways, for a total of:

12x11x10x9x8 different combinations.

Now you have to take in account that 5x4x3x2 are repetitions. So you have to divide the previos counting by 5x4x3x2.

(12x11x10x9x8)/(5x4x3x2) = 792 different subcommittees.

Also, you can use the formula for combinations: C(m,n) = m! / (n! (m-n)!)

C (12, 5) = 12! / (5!) (12-5)! = [12x11x10x9x8x7!] / [5! 7!] = [12x11x10x9x8]/[5x4x3x2] = 792
3 0
3 years ago
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