<span>basically you write an exponential function for y=ab^x for a graph that includes (1,15) and (0,6)
then using (0,6) you get: 6 = ab^0
and using (1,15) you get 15 = ab^1
Equations:
a = 6
ab = 15
So, b = 15/6 = 5/2
Equation:
y = 6(5/2)^x</span>
Answer:
(the statement does not appear to be true)
Step-by-step explanation:
I don't think the statement is true, but you CAN compute the intercepted arc from the angle.
Note that BFDG is a convex quadrilateral, so its angles sum to 360. Since we know the inscribed circle touches the angle tangentially, angles BFD and BGD are both right angles, with a measure of 90 degrees.
Therefore, adding the angles together, we have:
alpha + 90 + 90 + <FDG = 360
Therefore, <FDG, the inscribed angle, is 180-alpha (ie, supplementary to alpha)
Subtracting a negative is the same as adding it.
4-(-3)=4+3=7
Answer:
A fraction bar labeled 1. Under the 1 are 2 boxes containing one-half. Under the 2 boxes are 4 boxes containing one-fourth. 2 one-fourths are circled.
Step-by-step explanation:
Answer:
42cm²
Step-by-step explanation:
because if the perimeter of the rectangle is 28 then the length is 5, 5 - 11 = 6, the formula for finding the trapezium is to add the 2 parallel sides, half them, then times them with the length so your sum will look like this, 5+9=14, (i knew the other side was 9 as the length of AB is the same as the length of FC, which is the one of the parallel sides of the trapezium) then we do 14÷2=7, finally we times 7 by 6 which is 42cm²
