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Zielflug [23.3K]
3 years ago
11

Assuming that a computer has been used to compute a P-value = 0.01635, what can we conclude about the following situation? A sim

ple random sample of 50 speeds (in mph) is obtained from cars traveling on a section of I-10 through Tallahassee. The sample has a mean of 72.3 mph and a standard deviation of 7.4 mph. Use a 0.05 significance level to test the claim that the mean speed of all cars is greater than the posted speed limit of 70 mph.
Mathematics
1 answer:
Arada [10]3 years ago
8 0

Answer:

Step-by-step explanation:

From the information given, we would write the hypothesis.

For the null hypothesis,

H0 : µ = 70

For the null hypothesis,

Ha : µ > 70

This is a right tailed test because of the symbol of greater than.

The decision rule is to reject the null hypothesis if the level of significance is greater than the p value and accept the null hypothesis if the level of significance is lesser than the p value.

Therefore, since the significance level, 0.05 > p value, 0.01635, then we would reject the null hypothesis. There is enough evidence that the mean speed of all cars is greater than the posted speed limit of 70 mph.

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Use Cramer Rule to solve the following system: 8x−5y=70 and 9x+7y=3
nlexa [21]

Answer:

(x,y) = (5,-6)

Step-by-step explanation:

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y = \dfrac{D_y}{D}\\\\\\~~=\dfrac{\begin{vmatrix} 8& 70 \\9&3 \end{vmatrix}}{\begin{vmatrix} 8& -5\\ 9& 7\end{vmatrix}}\\\\\\~~=\dfrac{(8)(3) -(70)(9)}{(8)(7)-(-5)(9)}\\\\\\~~=\dfrac{24-630}{56+45}\\\\\\~~=-\dfrac{606}{101}\\\\\\~~=-6

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See attachment for plot

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<u>The plot at 1 and 2 minutes</u>

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<em>See attachment for plot</em>

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