Erm i could you explain more of the question we can't go by just this
The vertical asymptote of the function f(x) = 3 log(x + 3) is x = -3
Step-by-step explanation:
A symptote is a line that a curve approaches but never touches
- The vertical asymptote of a logarithmic function is at the zero of the argument
- f(x) = log(argument) has vertical aymptotes at argument = 0
∵ f(x) = 3 ㏒(x + 3)
∵ The argument is (x + 3)
- Equate the argument by zero
∵ x + 3 = 0
- Subtract 3 from both sides
∴ x = -3
- The vertical asymptote of a logarithmic function is at the zero
of the argument
∴ The vertical asympotote of f(x) is x = -3
The vertical asymptote of the function f(x) = 3 log(x + 3) is x = -3
Learn more:
You can learn more about the logarithmic functions in brainly.com/question/11921476
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3x+5=2x-10
-2x -2x
X+5=-10
-5 -5
X=-15
3(-15)+y=5
-45+y=5
+45 +45
y=50
2(-15)-y=10
-30-y=10
+30 +30
-y=40
Divide by -1 on both sides
y=-40
Answer:
The absolute value of -9 is less than 9 I'm pretty sure