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dimulka [17.4K]
3 years ago
11

Janice’s twin sister, Janette, is also working to save money over the summer. She is in college and needs $1,000 for her books f

or the year. At the beginning of the summer, she has $175 in her account and plans to save $75 per week. How many weeks until she has enough?
Mathematics
1 answer:
valina [46]3 years ago
4 0

Answer:

A. It will take 13 weeks until she gets the money nd she will have $50 left!

Step-by-step explanation:

Please mark brainliest! Have a nice day!

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Mrs. Howard is hosting a catered dinner party to celebrate her daughter's graduation. The catering company she plans to use char
Airida [17]
Hi there! The answer is 72 guests.

To find our answer we need to set up and solve an equation. Let the total number of guests be represented by g. The cost per guest is $13.50
Therefore the cost for all of the guests will be $13.50 × g.

To find the total cost we need to add the additional fee of $540 to cover linens and tableware.

Now we've found our equation.
13.5g + 540 = 1512

Subtract 540.
13.5g = 972

Divide by 13.5
g = \frac{972}{13.5} = 72

Therefore, there are 72 guests. The answer is 72.
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3x=20+2x2=24
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At a local university, a sample of 49 evening students was selected in order to determine whether the average age of the evening
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Answer:

z=\frac{23-21}{\frac{3.5}{\sqrt{49}}}=4    

p_v =2*P(z>4)=0.0000633  

When we compare the significance level \alpha=0.1 we see that p_v so we can reject the null hypothesis at 10% of significance. So the  the true mean is difference from 21 at this significance level.

Step-by-step explanation:

Data given and notation  

\bar X=23 represent the sample mean

\sigma=3.5 represent the population standard deviation

n=49 sample size  

\mu_o =21 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the average age of the evening students is significantly different from 21, the system of hypothesis would be:  

Null hypothesis:\mu = 21  

Alternative hypothesis:\mu \neq 21  

The statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{23-21}{\frac{3.5}{\sqrt{49}}}=4    

P-value

Since is a two sided test the p value would be:  

p_v =2*P(z>4)=0.0000633  

Conclusion  

When we compare the significance level \alpha=0.1 we see that p_v so we can reject the null hypothesis at 10% of significance. So the  the true mean is difference from 21 at this significance level.

8 0
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