1). Make your equation equal to 0
2). Then plug in your numbers to the quadratic equation
I'd start by writing an equation for each of the right triangles. (Pythagorean theorem)
y² + 9² = z²
x² + z² = (4+9)²
4² + y² = x²
we want to find z so combine the equations by substituting the other variables x,y out.
substitute y² for (x² - 4²) in 1st equation.
(x² - 4²) + 9² = z²
now by rearranging the 2nd equation we can substitute x² for (13² - z²)
(13² - z²) - 4² + 9² = z²
169 - z² - 16 + 81 = z²
234 - z² = z²
234 = 2z²
234/2 = z²
117 = z²
√(117) = z
√(9*13) = z
3√(13) = z
13 goes in the box
3:5 = 64cm
3x+5x= 64
8x=64
x=8
Therefore,
3x=8×3
=24
5x=8×5
=40
3x+5x=64cm
C I believe , sorry if I’m wrong
Ben - 8 years old
Ishaan - 2 years old
