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erik [133]
3 years ago
9

6. Find the function with x-intercepts (-3,0) and (5,0), which also goes through the point (1,8)

Mathematics
1 answer:
Yakvenalex [24]3 years ago
4 0

Answer:

f(x) = (-1/2)(x^2 + 8x - 15)

Step-by-step explanation:

This function has two roots:  -3 and 5.  Most likely it is a quadratic (all of which have two roots).

Then f(x) = a(x + 3)(x - 5)

The graph goes through (1. 8):  Therefore, y = 8 when x = 1:

f(1) = a(1 + 3)(1 - 5) = 8, or

        a(4)(-4) = 8, or

            -16a = 8, which leads to a = -1/2.

Thus the quadratic in question is f(x) = (-1/2)(x + 3)(x - 5), or

                                                        f(x) = (-1/2)(x^2 + 8x - 15)

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in a roulette wheel there are 38 numbered slots: 36 slots are the numbers 1 through 36 and the remaining two slots are 0 and 00.
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roulette consists in placing a small ball in a roulette wheel, Probability (Roulette ball not landing on red) = 10 / 19

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Probability (Roulette ball not landing on red) = 1 - Probability (Roulette ball landing on red)

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1 year ago
Estimate the perimeter, and also please show your work!
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Answer:

You can also just find the area and times that by 4

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Step-by-step explanation:

7 0
2 years ago
The length of a rectangular flower bed is 2ft longer than the width. If the area is 6ft, then what are the exact length and widt
Marizza181 [45]

Answer:

Exact dimensions:

width=-1+\sqrt{7}

length=-1+\sqrt{7}+2

length=1+\sqrt{7}

Approximate dimensions:

width=1.64575ft

length=1.64575+2

length=3.64575ft

Step-by-step explanation:

Let's assume width of rectangle is w ft

The length of a rectangular flower bed is 2ft longer than the width

so,

length =w+2

L=w+2

now, we can find area

A=L\times W

now, we can plug it

A=(w+2)\times w

A=w^2+2w

we are given area =6

so, we can set it equal

and then we can solve for w

w^2+2w=6

w^2+2w-6=0

we can use quadratic formula

ax^2+bx+c=0

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

now, we can compare and find a,b and c

a=1 , b=2 , c=-6

w=\frac{-2\pm \sqrt{2^2-4\cdot \:1\left(-6\right)}}{2\cdot \:1}

w=-1+\sqrt{7},\:w=-1-\sqrt{7}

we know that dimension can never be negative

so, we will only consider positive value

Exact dimensions:

width=-1+\sqrt{7}

length=-1+\sqrt{7}+2

length=1+\sqrt{7}

Approximate dimensions:

width=1.64575ft

length=1.64575+2

length=3.64575ft

7 0
3 years ago
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