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erik [133]
3 years ago
9

6. Find the function with x-intercepts (-3,0) and (5,0), which also goes through the point (1,8)

Mathematics
1 answer:
Yakvenalex [24]3 years ago
4 0

Answer:

f(x) = (-1/2)(x^2 + 8x - 15)

Step-by-step explanation:

This function has two roots:  -3 and 5.  Most likely it is a quadratic (all of which have two roots).

Then f(x) = a(x + 3)(x - 5)

The graph goes through (1. 8):  Therefore, y = 8 when x = 1:

f(1) = a(1 + 3)(1 - 5) = 8, or

        a(4)(-4) = 8, or

            -16a = 8, which leads to a = -1/2.

Thus the quadratic in question is f(x) = (-1/2)(x + 3)(x - 5), or

                                                        f(x) = (-1/2)(x^2 + 8x - 15)

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Answer:

Step-by-step explanation:

Combine like terms. Like terms have same variable with same power

a) (2xy + 4x) + (15xy - 5x)  = <u>2xy + 15xy</u> +<u> 4x - 5x</u>

                                         = 17xy - x

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e) (2x² + 7x - 2 + 9y) - (13x + 4x² + 5 - 6y)

Additive inverse of  13x + 4x² + 5 - 6y = -13x + 4x² - 5 + 6y

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                    = 2x² - 4x² + 7x -13x -2 - 5 + 9y + 6y

                    = -2x²  - 6x  - 7 + 15y

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