Answer:
<em>Option B</em>
Step-by-step explanation:
We can approach this problem through the formula for distance between points, but I can think of a more easier approach. This line forms a triangle with the x and y axis, a right triangle with the legs being 2 and 1 units. The line with which we must find the distance of acts as the hypotenuse of this triangle, so let us apply Pythagorean Theorem to solve for the length of the line;
<em>Solution; Option B</em>
Mid point b/w pair of coordinate (xo ,yo) ,(x1,y1)
X = xo+x1/2
y= yo+y1/2
thus mid point between (-8,-8),(4,8)
X = -8+4/2= -2
y= -8+8/2 = 0
(-2,0) will be the midpoint
V = C(1 - (T/N)).......for C ....multiply both sides by N
NV = CN - CT
NV = C(N - T) ...divide both sides by (N-T)
NV / (N - T) = C
V = C(1 - (T/N))...for T ...multiply both sides by N
NV = CN - CT ....subtract CN from both sides
NV - CN = - CT....divide both sides by -C
(NV - CN) / -C = T or (CN - NV)/ C = T
Answer:
45
Step-by-step explanation:
Answer:
2.67
Step-by-step explanation:
