The Answer is : A, B , C .
Simple...
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Thus, your answer.
Answer:
The answer to this question is the option "A".
Explanation:
In this question, the answer is Increase in complexity because, In computer science, the computerized or simply complexity is an algorithm. In this algorithm, the number of the resource is required for moving it (a quality separate to “complexity” in a conventional reason). So in this question the answer is option A that is Increase in complexity.
Answer:
The answer is "Option C"
Explanation:
The content management system promotes the accurate coding technique, which is used to monitor incorrect encoding, in which the comprehensive code is used, that compiles the code to defining or covering two or more CPT part code, packaged as one package, that's why "option c" is correct and other were wrong which can be defined as follows:
- In option A, It is wrong because code can't be a component code.
- Option B and Option D is wrong because it uses a comprehensive code only.
Answer:
def odd_even(N):
for number in range(0, N+1):
if number % 2 == 0:
print(str(number) + " is even")
elif number % 2 == 1:
print(str(number) +" is odd")
odd_even(5)
Explanation:
- Create a method called odd_even that takes one parameter, N
- Initialize a for loop that iterates through 0 to N
Inside the loop, check if module of the number with respect to 2 is equal to 0. If yes, print it as even number. If module of the number with respect to 2 is equal to 1, print it as odd number
Call the method
