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Komok [63]
2 years ago
6

PLEASE a help me (pre algebra)

Mathematics
2 answers:
Marina86 [1]2 years ago
6 0
I don’t like math it’s hard
irakobra [83]2 years ago
4 0

Answer:

it's in order

1.   j: 71

2. j: 16

3. j: 10

4. j: 68

5. j: 61

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What is the domain and range for:<br> y = arcsin(tanx)
Semmy [17]
The graph looks like this, on the enclosed pic:
One feature is that it's periodic and torn (has cut-off points), meaning the domain is the same as in case of tan(x): x€R and x =/= π/2+πn.
The range equals the range of arcsin(x): -π/2<=y<=π/2 OR y€[-π/2;π/2]
Hope could understand and if it helped! :)

7 0
3 years ago
Carly spend 10 hours a day working at her job what percentage of her day does she spend at work ?
AlladinOne [14]
10/24 x 100 = 41.66
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3 0
3 years ago
Read 2 more answers
Using a linear approximation, estimate f(2.1), given that f(2) = 5 and f'(x) = √3x-1.
algol [13]

Answer:

f\left( {2.1} \right) \approx 5.22360.

Step-by-step explanation:

The linear approximation is given by the equation

                            {f\left( x \right) \approx L\left( x \right) }={ f\left( a \right) + f^\prime\left( a \right)\left( {x - a} \right).}

Linear approximation is a good way to approximate values of f(x) as long as you stay close to the point x= a, but the farther you get from x=a, the worse your approximation.

We know that,

a=2\\f(2) = 5\\f'(x) = \sqrt{3x-1}

Next, we need to plug in the known values and calculate the value of f(2.1):

{L\left( x \right) = f\left( 2 \right) + f^\prime\left( 2 \right)\left( {x - 2} \right) }=5+\sqrt{3(2)-1}(x-2) =5+\sqrt{5}(x-2)

Then

f\left( {2.1} \right) \approx 5+\sqrt{5}(2.1-2)\approx5.22360.

6 0
3 years ago
Pls help and a give u a brilliant
fomenos

Answer:

Instead of 16 write 36

Step-by-step explanation:

when we see this carefully 4/6= 24/16

This is an equivalent fraction

when we multiply 4×6 we get 24 so we must multiply 6 with 6 . so the answer is 36.

4 0
3 years ago
Find all geometric sequences such that the sum of the first two terms is 24 and the sum of the first three terms is 26.
Serga [27]

Answer:

<h3>The nth term Tn = -8(-1/4)^(n-1) or Tn = 6(1/3)^(n-1) can be used to find all geometric sequences</h3>

Step-by-step explanation:

Let the first three terms be a/r, a, ar... where a is the first term and r is the common ratio of the geometric sequence.

If the sum of the first two term is 24, then a/r + a = 24...(1)

and the sum of the first three terms is 26.. then a/r+a+ar = 26...(2)

Substtituting equation 1 into 2 we have;

24+ar = 26

ar = 2

a = 2/r ...(3)

Substituting a = 2/r into equation 1 will give;

(2/r))/r+2/r = 24

2/r²+2/r = 24

(2+2r)/r² = 24

2+2r = 24r²

1+r = 12r²

12r²-r-1 = 0

12r²-4r+3r -1 = 0

4r(3r-1)+1(3r-1) = 0

(4r+1)(3r-1) = 0

r = -1/4 0r 1/3

Since a= 2/r then a = 2/(-1/4)or  a = 2/(1/3)

a = -8 or 6

All the geometric sequence can be found by simply knowing the formula for heir nth term. nth term of  a geometric sequence is expressed as

if r = -1/4 and a = -8

Tn = -8(-1/4)^(n-1)

if r = 1/3 and a = 6

Tn = 6(1/3)^(n-1)

The nth term of the sequence above can be used to find all the geometric sequence where n is the number of terms

6 0
3 years ago
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