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vlabodo [156]
3 years ago
8

A pharmaceutical company has developed a test for a scarce disease that is present in 0.5% of the population. The test is 98% ac

curate in determining a positive result, and the chance of a false positive is 4%. What is the probability that someone who tests positive actually has the disease?
Mathematics
2 answers:
marysya [2.9K]3 years ago
7 0
I'm pretty sure it is 3 percent. I may be wrong.

ioda3 years ago
5 0
The probability is 3%
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Janet has a bag of marbles. The bag contains 10 blue, 5 green, and 1 orange marble. She will randomly select 1 marble from the b
Musya8 [376]

Answer:

1/16

Step-by-step explanation:

6 0
3 years ago
Forty percent of the 30 members of the drama club were members of the senior class
andriy [413]

10%of30=3

3x4=12

A. 40%of 30=12 senior class members.

B. 60% of the class were not senior class members

4 0
2 years ago
Read 2 more answers
How do i solve that question?
yawa3891 [41]

a) The solution of this <em>ordinary</em> differential equation is y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2   } }.

b) The integrating factor for the <em>ordinary</em> differential equation is -\frac{1}{x}.

The <em>particular</em> solution of the <em>ordinary</em> differential equation is y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}.

<h3>How to solve ordinary differential equations</h3>

a) In this case we need to separate each variable (y, t) in each side of the identity:

6\cdot \frac{dy}{dt} = y^{4}\cdot \sin^{4} t (1)

6\int {\frac{dy}{y^{4}} } = \int {\sin^{4}t} \, dt + C

Where C is the integration constant.

By table of integrals we find the solution for each integral:

-\frac{2}{y^{3}} = \frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32} + C

If we know that x = 0 and y = 1<em>, </em>then the integration constant is C = -2.

The solution of this <em>ordinary</em> differential equation is y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2   } }. \blacksquare

b) In this case we need to solve a first order ordinary differential equation of the following form:

\frac{dy}{dx} + p(x) \cdot y = q(x) (2)

Where:

  • p(x) - Integrating factor
  • q(x) - Particular function

Hence, the ordinary differential equation is equivalent to this form:

\frac{dy}{dx} -\frac{1}{x}\cdot y = x^{2}+\frac{1}{x} (3)

The integrating factor for the <em>ordinary</em> differential equation is -\frac{1}{x}. \blacksquare

The solution for (2) is presented below:

y = e^{-\int {p(x)} \, dx }\cdot \int {e^{\int {p(x)} \, dx }}\cdot q(x) \, dx + C (4)

Where C is the integration constant.

If we know that p(x) = -\frac{1}{x} and q(x) = x^{2} + \frac{1}{x}, then the solution of the ordinary differential equation is:

y = x \int {x^{-1}\cdot \left(x^{2}+\frac{1}{x} \right)} \, dx + C

y = x\int {x} \, dx + x\int\, dx + C

y = \frac{x^{3}}{2}+x^{2}+C

If we know that x = 1 and y = -1, then the particular solution is:

y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}

The <em>particular</em> solution of the <em>ordinary</em> differential equation is y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}. \blacksquare

To learn more on ordinary differential equations, we kindly invite to check this verified question: brainly.com/question/25731911

3 0
3 years ago
Identify the mean of each distribution. Distribution A Mean = Distribution B Mean = Distribution C Mean =.
mariarad [96]

Answer:

50

100

200


B,C,A

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Write -33/12 as a mixed number in reduced form. -2 -1 -2 -2
AysviL [449]
-33/12. Lets forget the negative symbol.

12 goes into 33, 2 times with 9 remaining.

So now get the negative sign back.

It will be -2 9/12 but you can reduce that to -2 3/4.

Hope this helps :)
7 0
3 years ago
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