Answer:
64°
Step-by-step explanation:
∠RQP = 46°
∠PRQ = 180° - 110° = 70°
∠PRQ + ∠RQP + <u>∠RPQ</u> = 180°
70° + 46 + <u>∠RPQ</u> = 180°
116° + <u>∠RPQ</u> = 180°
Find <u>∠RPQ</u>
<u>∠RPQ</u> = 180° - 116° = 64°
Given
Answer
The graph touches the x-axis at -6
Hence x = -6 is the zero of the graph.
F(-11/5)=5(-11/5)+6
f(-11/5) = -11+6
<span>f(-11/5) = -5
Hope this helps!</span>
Method:
First place the replace of p and r using brackets.
= 3(6) + 11.7(7)
3 times 6 is 18 and 11.7 times 7 is 81.9
= 18 + 81.9
add one and one together you get
= 99.9
<em>hope </em><em>it </em><em>helps</em>