Step-by-step explanation:
___is the capacity to influence
behaviour
Select one:
a. Self-interest
b. Coercion
c. Power
d. Potential
= Power___is the capacity to influence
behaviour
Select one:
a. Self-interest
b. Coercion
c. Power
d. Potential
= Power___is the capacity to influence
behaviour
Select one:
a. Self-interest
b. Coercion
c. Power
d. Potential
= Power___is the capacity to influence
behaviour
Select one:
a. Self-interest
b. Coercion
c. Power
d. Potential
= Power___is the capacity to influence
behaviour
Select one:
a. Self-interest
b. Coercion
c. Power
d. Potential
= Power___is the capacity to influence
behaviour
Select one:
a. Self-interest
b. Coercion
c. Power
d. Potential
= Power___is the capacity to influence
behaviour
Select one:
a. Self-interest
b. Coercion
c. Power
d. Potential
= Power___is the capacity to influence
behaviour
Select one:
a. Self-interest
b. Coercion
c. Power
d. Potential
= Power___is the capacity to influence
behaviour
Select one:
a. Self-interest
b. Coercion
c. Power
d. Potential
= Power___is the capacity to influence
behaviour
Select one:
a. Self-interest
b. Coercion
c. Power
d. Potential
= Power___is the capacity to influence
behaviour
Select one:
a. Self-interest
b. Coercion
c. Power
d. Potential
= Power___is the capacity to influence
behaviour
Select one:
a. Self-interest
b. Coercion
c. Power
d. Potential
= Power
Answer: A) .1587
Step-by-step explanation:
Given : The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.30 ounces and a standard deviation of 0.20 ounce.
i.e.
and 
Let x denotes the amount of soda in any can.
Every can that has more than 12.50 ounces of soda poured into it must go through a special cleaning process before it can be sold.
Then, the probability that a randomly selected can will need to go through the mentioned process = probability that a randomly selected can has more than 12.50 ounces of soda poured into it =
![P(x>12.50)=1-P(x\leq12.50)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{12.50-12.30}{0.20})\\\\=1-P(z\leq1)\ \ [\because z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.8413\ \ \ [\text{By z-table}]\\\\=0.1587](https://tex.z-dn.net/?f=P%28x%3E12.50%29%3D1-P%28x%5Cleq12.50%29%5C%5C%5C%5C%3D1-P%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5Cleq%5Cdfrac%7B12.50-12.30%7D%7B0.20%7D%29%5C%5C%5C%5C%3D1-P%28z%5Cleq1%29%5C%20%5C%20%5B%5Cbecause%20z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-0.8413%5C%20%5C%20%5C%20%5B%5Ctext%7BBy%20z-table%7D%5D%5C%5C%5C%5C%3D0.1587)
Hence, the required probability= A) 0.1587
9514 1404 393
Answer:
A. 3×3
B. [0, 1, 5]
C. (rows, columns) = (# equations, # variables) for matrix A; vector x remains unchanged; vector b has a row for each equation.
Step-by-step explanation:
A. The matrix A has a row for each equation and a column for each variable. The entries in each column of a given row are the coefficients of the corresponding variable in the equation the row represents. If the variable is missing, its coefficient is zero.
This system of equations has 3 equations in 3 variables, so matrix A has dimensions ...
A dimensions = (rows, columns) = (# equations, # variables) = (3, 3)
Matrix A is 3×3.
__
B. The second row of A represents the second equation:

The coefficients of the variables are 0, 1, 5. These are the entries in row 2 of matrix A.
__
C. As stated in part A, the size of matrix A will match the number of equations and variables in the system. If the number of variables remains the same, the number of rows of A (and b) will reflect the number of equations. (The number of columns of A (and rows of x) will reflect the number of variables.)
Answer:

Step-by-step explanation:
<h2>
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<em><u>THE</u></em><em><u> </u></em><em><u>HEI</u></em><em><u>GHT</u></em><em><u> OF</u></em><em><u> </u></em><em><u>CYLI</u></em><em><u>NDER</u></em><em><u> IS</u></em><em><u> </u></em><em><u>4</u></em><em><u>X</u></em><em><u> </u></em><em><u>UNITS</u></em><em><u> </u></em><em><u>.</u></em>
<em><u>☞</u></em><em><u>ÙR</u></em><em><u> ÃÑSWER</u></em><em><u> </u></em><em><u>HØPE</u></em><em><u> IT</u></em><em><u> HELPS</u></em><em><u> YOU</u></em><em><u> ✌️</u></em>
Answer:

Step-by-step explanation:
