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3 years ago

Create a fraction that is equivalent to 3/4 explain the steps you took to create your fraction

Mathematics

1 answer:

serg [7]3 years ago

4 0

6/8. multiply 3/4 by 2 and there is your answer.

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To multiply 3 and 14 together, you could multiply 3 by 10 and add it to 3 times 4. Which property allows you to do that?

iVinArrow [24]

Associative property
will allow you to do this

4 0

3 years ago

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Which conversion requires division?

Tom [10]

Answer:

Step-by-step explanation:

it is going from low to high

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3 years ago

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At 8:00 pm on Wednesday a friend in San Francisco, California (based on 120 degrees W) calls a friend in Miami, Florida (75 degr

____ [38]

Answer:

11:00 pm Wednesday

Step-by-step explanation:

Given

Current Time in San Francisco:

$Time = 8:00pm\ (Wednesday)$ at 120 deg W

Required

Determine the current time at Miami at 75 deg W

First, we need to calculate the hours difference between San Franciso and Miami

$Hours = 120\deg - 75\deg$

$Hours = 45\deg$

Convert degrees to hours.

$15\deg =1\ hour$

So:

$Hours = 45\deg$

$Hours = 3 * 15\deg$

$Hours = 3 * 1\ hour$

$Hours = 3\ hours$

The above is the time difference between San Francisco and Miami;

The time in Miami is then calculated as:

$Miami = 8:00pm + 3\ hours$

$Miami = 11:00pm$

Hence, the time at Miami is: 11:00 pm Wednesday

6 0

3 years ago

Solve 4 - 2(-5a - 10)=30 and justify each step

Sergeeva-Olga [200]

First you would do parenthesis according to the PEMDAS(Parenthesis, Exponents, Multiply, Divide, Add, Subtract) Rule

4 -2(-5a -10) = 30

4 + 10a + 20 = 30

Now you need to add 4 and 20 because they are on the same side

24 + 10a = 30

Now subtract 24 on both sides

24 + 10a = 30

-24. -24

10a = 6

Last divide 10 from both sides

10a/10. = 6/10

a= 6/10

Last simplify (optional but recommended)

a = 3/5 or 0.6

Hope this helped :)

A = 0.6

5 0

3 years ago

Write an iterated integral for ModifyingBelow Integral from nothing to nothing Integral from nothing to nothing Integral from no

coldgirl [10]

With the given order of integration, the interval over D is

$\displaystyle \iiint_D f(x,y,z) \, dV = \int_{-3}^{3} \int_{-\sqrt{9-x^2}}^{\sqrt{9-x^2}} \int_{-\sqrt{9-x^2-z^2}}^{\sqrt{9-x^2-z^2}} f(x,y,z) \, dy \, dz \, dx$

8 0

3 years ago