In this problem, we can imagine that all the points
connect to form a triangle. The three point or vertices are located on the
pitcher mount, the home plate and where the outfielder catches the ball. So in
this case we are given two sides of the triangle and the angle in between the
two sides.
<span>With the following conditions, we can use the cosine law
to solve for the unknown 3rd side. The formula is:</span>
c^2 = a^2 + b^2 – 2 a b cos θ
Where,
a = 60.5 ft
b = 195 ft
θ = 32°
Substituting the given values:
c^2 = (60.5)^2 + (195)^2 – 2 (60.5) (195) cos 32
c^2 = 3660.25 + 38025 – 20009.7
c^2 = 21,675.56
c = 147.23 ft
<span>Therefore the outfielder throws the ball at a distance of
147.23 ft towards the home plate.</span>
I believe this would be correct.
Answer:
50 ft²
Step-by-step explanation:
If W is the width and L is the length, then:
L = W + 5
2L + 2W = 30
Solve the system of equations with substitution or elimination. Using substitution:
2(W + 5) + 2W = 30
2W + 10 + 2W = 30
4W = 20
W = 5
L = 10
The area of the rectangle is:
A = LW
A = 50 ft²
Answer:
Step-by-step explanation:
Its symbols from ancient Egypt welded in to the rock that the gods had walked on