5n = 3(n + 2) + 10
5n = 3n + 16
12n = 16
n = 8
8 is smaller integer and 10 is the larger.
Answer:
Least number of bus require for trip = 5 buses (Approx)
Step-by-step explanation:
Given:
Total number of classes = 9
Number of student in each class = 25
Number of teacher = 4
Number of chaperones = Double of teacher
Bus hold = 45 people
Find:
Least number of bus require for trip
Computation:
Total number of student = 9 × 25
Total number of student = 225
Number of chaperones = 4 × 2
Number of chaperones = 8
Total people = 225 + 8 + 4
Total people = 237
Least number of bus require for trip = Total people / Bus hold
Least number of bus require for trip = 237 / 45
Least number of bus require for trip = 5.266
Least number of bus require for trip = 5 buses (Approx)
The Real Answer is B: Leasing a car for a certain period.
Hope this helps!
Answer:
is the answer
Step-by-step explanation:
First we need to substitute X and Y with their respective numbers
Then, following PEMDAS, We just need to simplify
