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Grace [21]
3 years ago
5

Need help with two questions regarding geometry

Mathematics
1 answer:
Oksanka [162]3 years ago
7 0

Answer:

I think the first one is 5200 and the second one is 3

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(Due Now!! HELP; I know how to do this I just don't have time)
qaws [65]

Answer:

It is C.

Step-by-step explanation:

You divided 6.57 by 3

and 3 by 3

3 by 3 = 1

6.57 = 2.19

3 so for every 1 pound it costs $2.19

6 0
3 years ago
Read 2 more answers
Over the past year, your friend Maura has been saving up for an epic road trip to travel across the country this summer. Her goa
Misha Larkins [42]
<span>"Give an example of a sound financial decision Maura might make to support this goal. Why is it sound?"
<span>
</span>She could choose to carefully budget her trip and avoid overspending at all costs. This prevents going into debt. She should also save up extra money in the event of an emergency.

</span><span>Then give an example of a poor financial decision Maura might make considering her goal. Why is it a poor decision?</span><span>

Not having a plan would be a poor decision on her part. She could end up spending too much and not realize how much money she has left.


I hope I helped!
</span>
8 0
3 years ago
britney is buying a hat at the mall. the shirt costs $31.59, and the hat costs $19.46. if Britney gives the sales clerk $100.00,
kiruha [24]

Answer: 48.95

Step-by-step explanation:

so first I would add together the cost of the shirt and hat

31.59 +19.46 = 51. 05

then I would take away the 51.05 ( the total ) from $100

100 - 51.05 = $48.95

So she would get $48.95 for change

7 0
3 years ago
Bruce drew a rectangle with a length of 8 3/4 inches and width of 6 inches. Brandon drew a rectangle with dimensions that were 1
AysviL [449]
The correct answer is D.
5 0
3 years ago
Read 2 more answers
assume that when adults with smartphones are randomly selected 15 use them in meetings or classes if 15 adult smartphones are ra
Tanzania [10]

Answer:

The probability that at least 4 of them use their smartphones is 0.1773.

Step-by-step explanation:

We are given that when adults with smartphones are randomly selected 15% use them in meetings or classes.

Also, 15 adult smartphones are randomly selected.

Let X = <em>Number of adults who use their smartphones</em>

The above situation can be represented through the binomial distribution;

P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; n = 0,1,2,3,.......

where, n = number of trials (samples) taken = 15 adult smartphones

           r = number of success = at least 4

           p = probability of success which in our question is the % of adults

                 who use them in meetings or classes, i.e. 15%.

So, X ~ Binom(n = 15, p = 0.15)

Now, the probability that at least 4 of them use their smartphones is given by = P(X \geq 4)

P(X \geq 4) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

= 1- \binom{15}{0}\times 0.15^{0} \times (1-0.15)^{15-0}-\binom{15}{1}\times 0.15^{1} \times (1-0.15)^{15-1}-\binom{15}{2}\times 0.15^{2} \times (1-0.15)^{15-2}-\binom{15}{3}\times 0.15^{3} \times (1-0.15)^{15-3}

= 1- (1\times 1\times 0.85^{15})-(15\times 0.15^{1} \times 0.85^{14})-(105 \times 0.15^{2} \times 0.85^{13})-(455 \times 0.15^{3} \times 0.85^{12})

= <u>0.1773</u>

3 0
3 years ago
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