Step-by-step explanation:
I assume it is meant to draw 2 blue balls in a row out of the full pool of balls (no other draws happen before or during this process).
tricky, your teacher.
I think the temptation is to simply say 1/3×1/3 = 1/9.
but is it ?
the probabilty to draw one blue ball out of the complete system (no ball missing) is
x / (6+4+x) = 1/3
x = (6+4+x)/3
3x = 6 + 4 + x = 10 + x
2x = 10
x = 5
so, we have a system of 6 orange, 4 green and 5 blue balls (15 all together) .
the probability at our first pull to draw a blue ball is the indicated 5/15 = 1/3.
but now, for the second ball, we have only 6 orange, 4 green and 4 blue balls in the pool (14 altogether).
and so the probability to draw a blue ball out of this is
4/14 = 2/7.
therefore, the probability to draw 2 blue balls is now the combination
1/3 × 2/7 = 2/21
aha ! so, it is a little bit less than the originally suspected probability of 1/9.
10.69 just use a calculator
Answer:
umm 1 2 3 4
Step-by-step explanation:
Answer:
<h3>Option 2 </h3>
angle 2 = 7x + 1 ( vertically opposite angles)
7x + 1 + 18x + 4 = 180° ( forming linear pair).
7x + 18x + 4 +1 = 180°
25x + 5 = 180°
25x = 180 - 5
25x = 175
x = 7°
angle 2 = 7(7)+ 1
= 50°
