Answer:
s = ![\sqrt[3]{999} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B999%7D%20%7D)
Step-by-step explanation:
V = s^3
Plug in the given volume.
999 = s^3
Take the third root of both sides to cancel out the ^3.
= s
Answer:
1.51
Step-by-step explanation:
Divide 7.55 by 5 and it equals 1.51
Answer:
781250
Step-by-step explanation:
Let y is the length of the farm field
Let x is the width of the farm field
Given that, no fencing is necessary along the rock wall, so we can find the perimeter of the farm is:
2x + y = 2500 feet
<=> y = 2500 -2x
The are of the farm has the following formula:
A = x*y
<=> A = x(2500 - 2x)
<=> A = 2500x -2
To have the maximum area of field in square feet, we need to use differentials to estimate:
= 2500 - 4x
Set
= 0, we have:
2500 - 4x = 0
<=> x = 625 feet.
=> y = 2500 - 2*625 = 1250 feet
So the maximum area of field is:
A = x*y = 625*1250 = 781250
Answer: 
<u>Step-by-step explanation:</u>
![\text{Use the distance formula: }d_AB=\sqrt{(x_A-x_B)^2+(y_A-y_B)^2}\\where\ (X_A, y_A)=(-3, -2)\\and\ (x_B,y_B)=(4, -7)\\\\\\d_AB=\sqrt{(-3-4)^2+[-2-(-7)]^2}\\\\.\quad =\sqrt{(-7)^2+(5)^2}\\\\.\quad =\sqrt{49+25}\\\\.\quad =\boxed{\sqrt{74}}](https://tex.z-dn.net/?f=%5Ctext%7BUse%20the%20distance%20formula%3A%20%7Dd_AB%3D%5Csqrt%7B%28x_A-x_B%29%5E2%2B%28y_A-y_B%29%5E2%7D%5C%5Cwhere%5C%20%28X_A%2C%20y_A%29%3D%28-3%2C%20-2%29%5C%5Cand%5C%20%28x_B%2Cy_B%29%3D%284%2C%20-7%29%5C%5C%5C%5C%5C%5Cd_AB%3D%5Csqrt%7B%28-3-4%29%5E2%2B%5B-2-%28-7%29%5D%5E2%7D%5C%5C%5C%5C.%5Cquad%20%3D%5Csqrt%7B%28-7%29%5E2%2B%285%29%5E2%7D%5C%5C%5C%5C.%5Cquad%20%3D%5Csqrt%7B49%2B25%7D%5C%5C%5C%5C.%5Cquad%20%3D%5Cboxed%7B%5Csqrt%7B74%7D%7D)