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Zinaida [17]
3 years ago
12

The two box plots summarize the number of hours spent in the weight room for all the players on the football team for two differ

ent high
schools
(a)
Which of the statements must be true about the distribution of data represented in the boxplots?
school
school 2
hours in the weight room
A Players at school 1 typically spent more time in the weight room than players at school 2.
B The middle half of the data for school 1 has more variability than the middle half of the data for school 2.
The median hours spent in the weight room for school 1 is less than the median for school 2 and the interquartile ranges for both schools are
equal.
The total number of hours spent in the weight room for players at school 2 is greater than the total number of hours for players at school 1.
(b) Explain your reasoning.
Mathematics
1 answer:
kolezko [41]3 years ago
5 0

Answer:

anyone got this answer? i need it badly

Step-by-step explanation:

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Answer: Use a bar or a number line. Try my example with -6.

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x + 2 − 2 > 12 − 2

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The table shows Mitch’s record for the last thirty par-3 holes he has played.
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The value of x is .... ?
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4 0
2 years ago
a rental car agency charges a flat fee of $110 plus $46 per day to rent a certain car. another agency charges a fee of $70 plus
insens350 [35]
First make and equation. Since you want to find the number of the day where both charge the same total amount, you would make the equation:
let x= the number of days
110+46(x)=70+54(x)
Solve:
110-70+46(x)=70-70+54(x)
40+46(x)=54(x)
40+46(x)-46(x)=54(x)-46(x)
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Therefore your answer would be 5 days
8 0
3 years ago
Read 2 more answers
PLSSS ANSWER, 35 pointss
xxTIMURxx [149]

Answer:

1.

(y - 5)(x + y)

2.

{(x - y)}(x - y   + a)

3.

(b - 3)(5b - 17)

Step-by-step explanation:

1. The given polynomial is

x(y - 5) - y(5 - y)

We need to factor the second part to get:

x(y - 5)  +  y(y - 5)

We factor y-5 to obtain:

(y - 5)(x + y)

2. We have

{(x - y)}^{2}  - a(y - x)

We again factor -1 from the second part to get:

{(x - y)}^{2} +  a(x- y)

We now factor x-y to get:

{(x - y)}^{2}   + a(x- y)

{(x - y)}(x - y   + a)

3. We have

2(3 - b) + 5 {(b - 3})^{2}

We factor negative 1 from the first part to get

- 2(b - 3) + 5 {(b - 3})^{2}

We now factor b-3 to get:

(b - 3)( - 2 + 5(b - 3))

We now simplify to get:

(b - 3)( - 2 + 5b - 15) = (b - 3)(5b - 17)

4 0
2 years ago
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