Question

What is the approximate volume of 280 g of chlorine gas (Cl2) at STP

Answer 1

Answer:

78 L Cl₂

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Chemistry

Atomic Structure

• Reading a Periodic Table
• STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

Stoichiometry

• Using Dimensional Analysis

Explanation:

Step 1: Define

280 g Cl₂

Step 2: Identify Conversions

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of Cl₂ - 2(35.45) = 70.90 g/mol

[STP] 1 mol = 22.4 L

Step 3: Convert

1. [DA] Set up:                                                                                                   $\displaystyle 280 \ g \ Cl_2(\frac{1 \ mol \ Cl_2}{79.90 \ g \ Cl_2})(\frac{22.4 \ L \ Cl_2}{1 \ mol \ Cl_2})$
2. [DA] Multiply/Divide [Cancel out units]:                                                       $\displaystyle 78.4981 \ L \ Cl_2$

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

78.4981 L Cl₂ ≈ 78 L Cl₂