4.48 mol Cl2. A reaction that produces 0.35 kg of BCl3 will use 4.48 mol of Cl2.
(a) The <em>balanced chemical equation </em>is
2B + 3Cl2 → 2BCl3
(b) Convert kilograms of BCl3 to moles of BCl3
MM: B = 10.81; Cl = 35.45; BCl3 = 117.16
Moles of BCl3 = 350 g BCl3 x (1 mol BCl3/117.16 g BCl3) = 2.987 mol BCl3
(c) Use the <em>molar ratio</em> of Cl2:BCl3 to calculate the moles of Cl2.
Moles of Cl2 = 2.987 mol BCl3 x (3 mol Cl2/2 mol BCl3) = 4.48 mol Cl2
Answer:
78
Explanation:
atomic number is number of protons
Answer: The new volume of gas is 28.5 L
Explanation:
The combined gas equation is,
where,
= initial pressure of gas = 1.00 atm (at STP)
= final pressure of gas = 102.6 kPa = 1.01 atm (1 kPa= 0.0098 atm)
= initial volume of gas = 10.0 L
= final volume of gas = ?
= initial temperature of gas =
(STP)
= final temperature of gas =
Now put all the given values in the above equation, we get:
The new volume of gas is 28.5 L
1,839,100 x 10^6
blah blah 20 characters
its times (x) 10 to the 6th power