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tatyana61 [14]
3 years ago
12

Plz help.................

Mathematics
1 answer:
zubka84 [21]3 years ago
4 0

Answer:

230°for the center of the circle

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What is the difference between a histogram and a cumulative histogram?
diamong [38]

Answer: The answer is provided below

Step-by-step explanation:

A histogram is a diagram which consist of rectangles whereby the area is proportional to frequency of a variable and the width is equal to class interval. A histogram is a commonly used graph that is used to show frequency distributions.

The cumulative histogram is a histogram whereby the vertical axis doesn't gives only the counts for a single bin, but gives the counts for that bin and all the bins for the maller values of a response variable.

Cumulative histograms are similar to normal histograms, but the main difference is that they graph cumulative frequencies unlike histograms that graph just frequencies.

3 0
3 years ago
Please help, solve for x
madreJ [45]

Answer: x=12

First, you do 8 squared = 4(4+x)

Then, you distribute and becomes a two-step equation.

64=16+4x.

So x=12.

Hope it helps :) Brainliest?

7 0
3 years ago
Question 3
mamaluj [8]
Question 4: a ray is formed by an endpoint and a line starting at the endpoint and going on forever in one direction
We cannot see angle MBW to be able to classify it
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4 years ago
Julia is allowed to watch no more than 5 hours of television a week. so far this week, she has watched 1.5 hours. write and solv
gulaghasi [49]
<span>X + 1.5 ≤ 5 X ≤ 3.5 "Julia is allows to watch no more than 5 hours of television" X ≤ 5 "She has watched 1.5 hours" X + 1.5 ≤ 5 So the inequality to solve is: X + 1.5 ≤ 5 Now to solve it, just subtract 1.5 from both sides: X + 1.5 ≤ 5 X + 1.5 - 1.5 ≤ 5 - 1.5 X ≤ 3.5 So Julia can watch up to 3.5 more hours of TV this week.</span>
5 0
3 years ago
If VT=2,what is the length of PT?
marusya05 [52]

Step-by-step explanation:

\underline{ \underline{ \text{Given : }}}

  • Perpendicular ( P ) = VT = 2
  • Base ( b ) = PT
  • \theta =  \tt{60 \degree}

\underline{ \underline{ \text{Solution}}} :

\tt{ \tan(60 \degree)  =  \frac{perpendicualar}{base}}

⟶ \tt{ \sqrt{3}  =  \frac{2}{PT}}

⟶ \tt{ \sqrt{3}  \: PT= 2}

⟶ \tt{PT =  \frac{2}{ \sqrt{3}} }

⟶ \tt{PT= \boxed{\tt{ \frac{2 \sqrt{3} }{{3} }}}}

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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6 0
3 years ago
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