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3 years ago

Point A is located at (-3, -5)

Mathematics

2 answers:

PtichkaEL [24]3 years ago

5 0

S’ would be located in (-9,-3)

olga2289 [7]3 years ago

3 0

A’ = (-3-6 , -5+2) = (-9 , -3)

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Can you guys help we with this question.

satela [25.4K]

Answer:

Step-by-step explanation:

(2x+1/(2x))^5 *(2x -1/(2x))^5

= ((2x)^2 -1/(2x)^2)^5 (a+b)*(a-b) =a2-b2

= (4x^2-1/4(x)^2)^5

now

x =4x^2. ,a = 1/4(x)^2 ,n =5

we have

general term = Cr *x^r *a^(n-r)

= Cr * (4x^2)^r * (1/4(x)^2)^(n-r)

= Cr *4^r * X^2r * 1/( 4^(n-r) *x^(2n-2r)

= Cr * 4^r/4^(n-r) * x^(2r)/x^(2n-2r)

= Cr * 4(2r-n) *x(4r-2n)

now for x^2

4r-2n = 2

4r -10=2

4r =12

r = 3

now for coeff

C(5,3) * 4^(2*3-5)

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5*4/(2*1)*4

4 0

2 years ago

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3 years ago

Among 46- to 51-year-olds, 28% say they have called a talk show while under the influence of peer pressurepeer pressure. Supp

sasho [114]

Answer:

0.8997, 0.9999

Step-by-step explanation:

Given that among 46- to 51-year-olds, 28% say they have called a talk show while under the influence of peer pressure.

i.e. X no of people who say they have called a talk show while under the influence of peer pressure is binomial with p = 0.28

Each person is independent of the other and there are only two outcomes

n =7

a) the probability that at least one has not called a talk showcalled a talk show while under the influence of peer pressure

= $P(Y\geq 1)$ where Y is binomial with p = 0.72

= $1-(1-0.72)^7\\=0.9999$

b) the probability that at least one has called a talk showcalled a talk show while under the influence of peer pressurepeer pressurethe probability that at least one has not called a talk showcalled a talk show while under the influence of peer pressure

= $P(x\geq 1) =1-P(0)\\= 1-(1-0.28)^7\\=0.8997$