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2 years ago

The area of the triangle below is 14.96 square inches. What is the length of the base?

Mathematics

2 answers:

Dvinal [7]2 years ago

5 0

Answer:

base = 6.8 in

Step-by-step explanation:

area of triangle = 1/2 base height

where height = 4.4 in

area = 14.96 in²

plugin values into the formula

14.96 = 1/2 base (4.4)

base = <u>14.96 (2)</u>

4.4

base = 6.8 in

fredd [130]2 years ago

3 0

Answer:

6.8

Step-by-step explanation:

To find the area of a triangle you have to do (bxh)÷2 the height is 4.4 and the area is 14.96. To find the base we have to go backwards we can multiply 14.96 x 2= 29.92

then we divide that by the height

29.92 ÷ 4.4= 6.8

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A triangle has one side that is 5 inches long and another that is 7 inches long. How many different lengths, in inches,are possi

lubasha [3.4K]

Answer:

2 < c < 12

Step-by-step explanation:

Let the last side of the triangle = c

The sum of any two sides must be greater than the third side. Let's say we have triangle ABC, where a = 5 inches and b = 7 inches

a + b > c (1)

a + c > b (2)

b + c > a (3)

From (1);

a + b > c

7 + 5 > c

c < 12

From (2):

a + c > b

7 + c > 5

7 - 5 < c

c > 2

From (3):

b + c > a

5 + c > 7

c > 7 - 5

c > 2

So the possible lengths of c are: 2 < c < 12

3 0

2 years ago

8. Lara invested a total of $1000 in two simple interest accounts. Account A pays

mixer [17]

Answer:

$200 at 5%
$800 at 6%

Step-by-step explanation:

Let x represent the amount invested at the higher rate. Then 1000-x is the amount invested at the lower rate. The total earnings are ...

0.05(1000-x) +0.06x = 58

50 +0.01x = 58 . . . . . . . . . . . simplify

0.01x = 8 . . . . . . . . . . . . . . . subtract 50

x = 800 . . . . . . . . . . . . . . . multiply by 100; amount at 6%

(1000-x) = 200 . . . . . . . find the amount invested at 5%

Lara invested $200 at 5% and $800 at 6%.

8 0

2 years ago

The owner of a golf course wants to determine if his golf course is more difficult than the one his friend owns. He has 8 golfer

dexar [7]

Answer:

The 90% confidence interval to estimate the average difference in scores between the two courses is (-1.088, 20.252).

Step-by-step explanation:

We have the standard deviation for the differences, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 7

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 7 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.9}{2} = 0.95$ . So we have T = 1.8946