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2 years ago

13

A door opening is 2 meters high. If there is a 39 centimeter gap between the top of Casey's head and the top of the door opening

, how tall is Casey?

1 answer:

sammy [17]2 years ago

8 0

You should find that Casey is 161 cm tall.

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I need help. What’s the equation

Mekhanik [1.2K]

Answer:

Step-by-step explanation:

y = mx + b

m = slope

so far what we know is

y = 1/2x + b

to find b we’ll plug in the point (2, 6)

6 = 1/2(2) + b

6 = 1 + b

b = 5

so now we plug in b to the equation to get

y = 1/2x + 5

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2 years ago

Slope:<br> what is the slope?

Len [333]

Answer: -2

Step-by-step explanation:

So basically I located the y-intercept first. Where is that? At the point (0,-2). Now from there, I found the nearest point on an intersecting grid line, in this case it would be (-1,0). So from the y-intercept, I looked at how many spaces I would have to move to get to (-1,0). You would have to go up 2 spaces and to the left 1 space. This is also written as 2/-1. Simplify this and you get -2! Hope this helped!

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2 years ago

assume that women's heights are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. find the

drek231 [11]

Answer:

65.3658 inches

Step-by-step explanation:

Let X be the height of a woman randomly choosen. We know tha X have a mean of 63.6 inches and a standard deviation of 2.5 inches. For an x value, the related z-score is given by z = (x-63.6)/2.5. We are looking for a value $x_{0}$ such that $P(X < x_{0}) = 0.76$ , but, $0.76 = P(X < x_{0}) = P((X-63.6)/2.5 < (x_{0}-63.6)/2.5) = P(Z < (x_{0}-63.6)/2.5)$ , i.e., $(x_{0}-63.6)/2.5$ is the 76th percentile of the standard normal distribution. So, $(x_{0}-63.6)/2.5 = 0.7063$ , $x_{0} =63.6+(2.5)(0.7063) = 65.3658$ . Therefore, the height of a woman who is at the 76th percentile is 65.3658 inches.

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3 years ago

What is the surface area

lesya692 [45]

Answer:660

Step-by-step explanation:

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2 years ago

Find the missing value of the direct variation (2,5) (5,y)

Karolina [17]

Answer:

The missing value y=12.5 and we have (5,12.5)

Step-by-step explanation:

The formula used for direct variation is:

$y\: \alpha \:x\\y=kx$

We need to find missing value (2,5)(5,y)

First we will find k, and then y

We have x=2, y=5

Find k:

$y=kx\\5=k(2)\\k=\frac{5}{2}\\k=2.5$

Now, we cam find missing value in (5,y)

We have x=5, k=2.5 and y=?

$y=kx\\y=2.5(5)\\y=12.5$

So, the missing value y=12.5 and we have (5,12.5)

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2 years ago