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2 years ago

= (-3 – (-2))+ (1 - (-4))

Mathematics

1 answer:

loris [4]2 years ago

4 0

Answer:

Step-by-step explanation:

(-3+2)+(1+4)

=-1+5

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All 6 members of the Valastro family have decided to

atroni [7]

Answer:

Step-by-step explanation:

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2 years ago

Match the concept with its definition and characteristics. i. A set of instructions (codes) that perform a specific task. ii. A

kogti [31]

First definition matches with expression, second matches with equation ,third matches with algorithm and fourth matches with equation.

Given four definitions of equation, expression, algorithm but mixed.

We have to match the definitions with appropriate term.

We know that expression is a combination of numbers, symbols, fraction, coefficients, indeterminants mostly not found in equal to form. It exhibits a behaviour only.

Algorithm is a computer programming to do a specific task in a predetermined way.

Equation is a relationship between two variables expressed in equal to form. In this we have to put the value of variables and the equation gives us a value.

Hence First definition matches with expression, second matches with equation ,third matches with algorithm and fourth matches with equation.

Learn more about algorithm at brainly.com/question/13800096

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7 0

1 year ago

<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bm%7D%20%20%3D%20n%20" id="TexFormula1" title=" {2}^{m} = n " alt=" {2}^{m} =

sveta [45]

Answer:

$\displaystyle n^3-\frac{1}{n^{2}}$

Step-by-step explanation:

<u>Exponents Properties</u>

We need to recall the following properties of exponents:

$(a^x)^y=(a^y)^x=a^{xy}$

$\displaystyle a^{-x}=\frac{1}{a^x}$

We are given the expression:

$2^m=n$

We need to express the following expression in terms of n.

$8^m-4^{-m}$

It's necessary to modify the expression to use the given equivalence.

Recall $8=2^3 \text{ and }4 = 2^2$ . Thus:

$(2^3)^m-(2^2)^{-m}$

Applying the property:

$(2^m)^3-(2^m)^{-2}$

Substituting the given expression:

$n^3-n^{-2}$

Or, equivalently:

$\mathbf{\displaystyle 8^m-4^{-m}= n^3-\frac{1}{n^{2}}}$

5 0

2 years ago

Math problem plz help

Firlakuza [10]

Answer:

5/2 x 1/2

Step-by-step explanation:

when you multiply fractions you multiply trait across meaning you do 5*1 and 2*2 which leaves you with 5/4 and that is equivalent to 1 &1/4

5 0

2 years ago

How to factor 6n2 - 6n - 12

alexandr402 [8]

We see that in these 3 terms, 6 is a common factor. So, let's factor out a 6:

$6n^2-6n-12 = 6(n^2-n-2)$

We can set this equal to 0 and factor by using the quadratic formula which is:

$x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

So, let's do just that:

$6(n^2-n-2) = 0$

Note that the 6 goes away if you divide both sides by 6. In this case, a = 1, b = -1, and c = -2. Let's plug that into the quadratic equation:

$\frac{1 \pm \sqrt{(-1)^2-4(1)(-2)} }{2(1)} = \frac{-1 \pm \sqrt{1-(-8)} }{2}$

$\frac{-1 \pm \sqrt{9} }{2} = {1, -2}$

So, we can write this as:

$6n^2 - 6n - 12 = 6(n-1)(n+2)$

Notice that the 6 comes back because it was only temporarily mad. And that the roots have opposite signs in the parentheses because to find the roots, you need to set each parentheses equal to 0 and solve for n. With that in mind, your final answer is 6(n-1)(n+2). Hope I could help you!

7 0

2 years ago