Answer:
20 kilograms of dough
Step-by-step explanation:
Given that;
12 kilograms working 6 hours
Rate = 12/6 kilogram per hour = 2 kilogram per hour
So,
In 10 hours he would produce;
Amount of dough = Time × rate
Time = 10 hours
= 10 hours × 2 kilograms per hour
= 20 kilograms of dough
Answer: 9,000
Step-by-step explanation: there are 9 number options for the first digit and 10 for the other 3, so 9x10x10x10=9000
Answer:
27 degrees
Step-by-step explanation:
The easy way is by remembering the formula (a-b)/2=c, where a is the larger angle, and b is the smallest angle. (90-36)/2=27.
The longer, more drawn out answer goes as follows. See the image to understand the notation I use:
- AOE + BOD + BOA + DOE = 360
- AOE + BOD = 90 + 36 = 126
- BOA + DOE = 360 - AOE - BOD = 234
- Since the sum of a triangle's angles is 180, ODE = (180 - DOE) / 2
- Likewise, OBA = (180 - BOA) / 2
- Since CDE is 180, CDO = 180 - ODE = 180 - (180 - DOE) / 2
- Likewise, CBA is 180, so CBO = 180 - OBA = 180 - (180 - BOA) / 2
- The interior angles of the irregular polygon CBOD add up to 360, so CBO + CDO + BOD + BCD = 360.
- Substituting what we already found, 180 - (180 - BOA)/2 + 180 - (180 - DOE)/2 + 36 + BCD = 360
- Cleaning it all up, we get 180 + (BOA + DOE)/2 + 36 + BCD = 360
- As we found in line 3, BOA + DOE = 234, so substituting that in, 180 + 117 + 36 + BCD = 360
- Finally, solving for BCD (360 - 36 - 117 - 180) we get our answer, 27
Note: The long drawn out method shown above is a way to derive the formula for the secant theorem. You do not need to use this method every time. Just remember, large angle minus small angle, all divided by 2. That is it.
Answer:
The hypotenuse is square root of 65
Step-by-step explanation:
a^2 + b^2 = c^2
legs of the right triangle are a and b. Just substitute 4 for a and 7 for b and solve.
4^2+7^2=16+49=65
c^2=65
Find the square root of both sides to get
c=the square root of 65
Start finding the slope of the line

using one of the points find the intercept and the standard form

the equation of the line is