<span>For every car
Mike earns------------------ >$200 plus 3% commission</span>
3 cars-----------------
> $200*3+$32,343*0.03=600+970.29=$1570.29
Total earnings
for a week is $1570.29
Given:
The number of male professors = 15.
The number of female professors = 9.
The number of male teaching assistants = 6.
The number of female teaching assistants = 12.
A person is selected randomly from the group.
Required:
We need to find the probability that the selected person is a professor or a male.
Explanation:
The total number of people in the group = 15+9+6+12 = 42
n(S) =The total number of people in the group

Let A be the event that the selected person is a professor or a male.
The number of people who are professors or male = 15+9+6 = 30
n(A)= The number of people who are professors or male.

Let P(A) be the probability that the selected person is a professor or a male.



Final answer:
The probability that the selected person is a professor or a male is 5/7.
Replace each of the x values given to see if they give 0.
0=(2/3)³+(2/3)²-1
0=(8/27)+(4/9)-1
0≠-0.259
0=(1)³+(1)²-1
0≠1
Therefore, you can see that the solution would have to be between 2/3 and 1.
Hope I helped :)
I think it would be 10x + 16 - 6
Answer:
21
Step-by-step explanation:
126/3=42
126-42=84
84/4=21
63 are dogs
42 are cats
and 21 are rabbits