Please help. problem involving magic squares
1 answer:
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Refer to the diagram shown below.
Given:
m∠A = 19°
c = 15
By definition,
sin A = a/c
Therefore
a = c*sin A = 15*sin(19°) = 4.8835
cos A = b/c
Therefore
b = c*cos A = 15*cos(19°) =14.1828
Answer:
The lengths are 4.88, 14.18, and 15.00 (nearest hundredth)
Given:
m∠A = 19°
c = 15
By definition,
sin A = a/c
Therefore
a = c*sin A = 15*sin(19°) = 4.8835
cos A = b/c
Therefore
b = c*cos A = 15*cos(19°) =14.1828
Answer:
The lengths are 4.88, 14.18, and 15.00 (nearest hundredth)
Answer:
a. 0.7291
b. 0.9968
c. 0.7259
Step-by-step explanation:
a. np and n(1-p) can be calculated as:
#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:
#Define Y:
Y~(11.04,5.7408)
Hence, the probability of 12 or fewer is 0.8291
b. The probability that 5 or more fish were caught.
#Using normal approximation:
Hence, the probability of catching 5+ is 0.9968
c. The probability of between 5 and 12 is calculated as;
-From b above and a ,
=0.7291
Hence, the probability of between 5 and 12 is 0.7259