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shutvik [7]
3 years ago
5

Please help. problem involving magic squares

Mathematics
1 answer:
lana [24]3 years ago
4 0

Step-by-step explanation:

First, let us find the magic sum in each row/column/diagonal.

Sum of numbers from 1 to 9 = 45.

45 divide by 3 rows = 15 each row.

The magic sum is 15.

For the diagonals, we have:

8 + 5 + x = Magic sum = 15,

6 + 5 + y = Magic sum = 15.

Therefore x = 2 and y = 4.

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13x-7y+4x
Vinvika [58]

Answer:

17−7

Step-by-step explanation:

Hope this helped good luck in your work!

4 0
3 years ago
-6 - 8 is equivalent to?<br> 6 + (-8)<br> -6 + 8<br> 6 + 8<br> -6 + (-8)
nadezda [96]
It is equivalent to:
-6 + (-8)
7 0
3 years ago
Read 2 more answers
Steven is driving to Texas pulling a 12 ft. boat. If he drives 150 miles in
ziro4ka [17]

Answer: 975

Step-by-step explanation:

Because you multiply 6 times 150 and then you add 75 because that is half of 150 and you only need one more mile

6 0
3 years ago
what are the lengths of the legs of a right triangle in which one acute angle measures 19° and the hypotensue is 15 units long?
givi [52]
Refer to the diagram shown below.

Given:
m∠A = 19°
c = 15

By definition,
sin A = a/c
Therefore
a = c*sin A = 15*sin(19°) = 4.8835

cos A = b/c
Therefore
b = c*cos A = 15*cos(19°) =14.1828

Answer:
The lengths are 4.88, 14.18, and 15.00  (nearest hundredth)  

6 0
3 years ago
In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist
Tcecarenko [31]

Answer:

a. 0.7291

b. 0.9968

c. 0.7259

Step-by-step explanation:

a. np and n(1-p) can be calculated as:

np=23\times 0.48\\\\=11.04\\\\n(1-p)=23(1-0.52)\\\\=11.96

#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:

\mu_x=11.04\\\\\sigma^2=np(1-p)=0.48\times 0.52\times 23=5.7408

#Define Y:

Y~(11.04,5.7408)

P(X\leq 12)\approx P(Y\leq 12.5)\\\\P(Z\leq \frac{(12.5-11.04)}{\sqrt{5.7408}})=\\\\=1-0.2709\\\\=0.7291

Hence, the probability of 12 or fewer is 0.8291

b. The  probability that 5 or more fish were caught.

#Using normal approximation:

P(X \geq 5) \approx P(Y \geq 4.5) = P(Z \geq\frac{ (4.5-11.04)}{\sqrt{(5.7408)}})\\\\=1-0.0032\\\\=0.9968

Hence, the probability of catching 5+ is 0.9968

c. The probability of between 5 and 12 is calculated as;

-From b above P(X\geq 5)=0.9968 and a ,P(X\leq 12)=0.7291

P(5\leq X\leq 120\approx P(4.5\leq Y\leq  12.5)\\\\=0.7291-(1-0.9968)\\\\=0.7259

Hence, the probability of between 5 and 12 is 0.7259

4 0
3 years ago
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