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LiRa [457]
3 years ago
7

What is the volume of the figure? Please help!

Mathematics
1 answer:
tangare [24]3 years ago
3 0

First, do edge x edge x edge to get volume of the cube.

Then, do (length x width x h eight) divided by 3 to get the volume of the rectangular pyramid.

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The pentagonal area is 20 cm square. Point A located in the pentagon and equidistant from all sides of the pentagon about 5 cm.
Maurinko [17]

Answer:

  about 8 cm

Step-by-step explanation:

The formula for the area of a regular polygon is ...

  A = 1/2Pa . . . . where P is the perimeter and "a" is the apothem, the distance from the center to a side

Filling in your numbers, we have ...

  20 cm^2 = (1/2)P(5 cm)

Dividing by the coefficient of P, we find ...

  2×(20 cm^2)/(5 cm) = P = 8 cm

The perimeter of the pentagon is about 8 cm.

_____

<em>Comment on the problem</em>

This calculation makes use of the area formula, as apparently intended. A regular pentagon with an apothem of about 5 cm will have an area of about 90.8 cm^2. The given geometry is impossible, as the pentagon is nearly 10 cm across. It cannot have a perimeter of only 8 cm.

5 0
3 years ago
Given that log 2 = 0.3010 and log 3 = 0.4771 , how can we find log 6 ? ​
bearhunter [10]

Answer:

\sf \log_{10}6=0.7781

Step-by-step explanation:

<u>Given</u>:

\sf \log_{10} 2 = 0.3010

\sf \log_{10} 3 = 0.4771

To find log₁₀ 6, first rewrite 6 as 3 · 2:

\sf \implies \log_{10}6=\log_{10}(3 \cdot 2)

\textsf{Apply the log product law}: \quad \log_axy=\log_ax + \log_ay

\implies \sf \log_{10}(3 \cdot 2)=\log_{10}3+\log_{10}2

Substituting the given values for log₁₀ 3 and log₁₀ 2:

\begin{aligned} \sf \implies \log_{10}3+\log_{10}2 & = \sf 0.4771+0.3010\\ & = \sf 0.7781 \end{aligned}

Therefore:

\sf \log_{10}6=0.7781

Learn more about logarithm laws here:

brainly.com/question/27953288

brainly.com/question/27963321

5 0
2 years ago
Read 2 more answers
$11.20 is 30% of what number
amm1812
The answer is $1120.00.
8 0
3 years ago
a small jet can fly 1,435 miles in 5 hours with a tailwind but only 1,215 miles in 5 hours into a headwind. find the speed of th
Ne4ueva [31]

Answer:

Speed of Jet in Still Air = 265 miles per hour

Speed of Wind = 22 miles per hour

Step-by-step explanation:

Let x be speed of jet

and c be speed of wind

We know D = RT, where

D is distance

R is rate

T is time

For first leg:

1435 miles in 5 hours, the rate is:

Rate = 287 mph

For second leg:

1215 miles in 5 hours, the rate is:

Rate = 243 mph

So 287 is with wind and 243 against wind, thus we can write:

x + c = 287

x - c = 243

Adding gives us:

2x = 530

x = 265 miles per hour [still rate]

Speed of wind:

x + c = 287

265 + c = 287

c = 22 miles per hour [speed of wind]

4 0
3 years ago
PLZ HURRY IT'S URGENT!!!!!!!
Dmitry_Shevchenko [17]

B. 12 and 25 is the answer.....

Hope this helps!

3 0
4 years ago
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