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Mrrafil [7]
3 years ago
14

Which equation has the same solution as 2x^2+16-10=0

Mathematics
1 answer:
Nastasia [14]3 years ago
3 0
2x^2 + 16x - 10 = 0
2(x^2 + 8x) - 10 = 0
2 [(x + 4)^2 - 16 ]- 10 = 0
[(x + 4)^2 - 16 - 5 = 0
(x + 4)^2 - 21 = 0
(x + 4)^2 = 21
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Step-by-step explanation:

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3 years ago
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Simplify the expression.
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4 years ago
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five consecutive terms of an arithmetic sequence have a sum of 40. The product of the middle and the two end terms is 224. Find
ratelena [41]
Let the five terms be: a, a + d, a + 2d, a + 3d, a + 4d, then
a + a + d + a + 2d + a + 3d + a + 4d = 5a + 15d = 40
i.e. a + 3d = 8
Also, (a + 2d)(a + 3d)(a + 4d) = 224
(a + 3d - d)(a + 3d)(a + 3d + d) = 224
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But a + 3d = 8
a + 3(6) = 8
a = 8 - 18 = -10

Therefore, the term of the sequence is: -10, -10 + 6, -10 + 2(6), -10 + 3(6), -10 + 4(6)
= -10, -4, -10 + 12, -10 + 18, -10 + 24
= -10, -4, 2, 8, 14

4 0
3 years ago
Please help thanks!!!
tankabanditka [31]

Answer:

30 or 780 is your answer for the first one. i dont know how to work out the answer for the 2 one im sorry :(

Step-by-step explanation:

13+12+5 = 30

13 x 12 x 5 = 780

I would go for 780

it seems more like to be the answer

5 0
3 years ago
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