In equation, let x be the number of male students
a be the number of adults
y be the number of female students.
x= 7a+1
a= x/7 -1
y= x/2 or (7a + 1)/ 2
a + b = 82, let b be the number of students.
a + (x + y) = 82
a + [7a+1 + (7a+1)/2] = 82
a + [{2(7a+1) + 7a+1} / 2] = 82
a + [(14a +2 + 7a +1) / 2] = 82
a + [(21a + 3) / 2] = 82
(2a+ 21a + 3) / 2 = 82
(23a + 3) / 2 = 82
23a + 3 = 164
23a = 164 -3
23a = 161
a = 7
x = 7(7) +1, 49+1 = 50 male students
y=x/2, 50/2, 25 female students
50(male students) + 25(female students) + 7 (adults) = 82
To find it it is
ax^2+bx+c
if the first term (a) is 1 then c=b/2
b=-1/4
(-1/4)/2=-1/4 times 1/2=-1/8
k=-1/8
Given
mean of 406 grams and a standard deviation of 27 grams.
Find
The heaviest 14% of fruits weigh more than how many grams?
Explanation
given
mean = 406 gms
standard deviation = 27 gms
using standard normal table ,
![\begin{gathered} P(Z>z)=14\% \\ 1-P(Zso , [tex]\begin{gathered} x=z\times\sigma+\mu \\ x=1.08\times27+406 \\ x=435.16 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20P%28Z%3Ez%29%3D14%5C%25%20%5C%5C%201-P%28Zso%20%2C%20%5Btex%5D%5Cbegin%7Bgathered%7D%20x%3Dz%5Ctimes%5Csigma%2B%5Cmu%20%5C%5C%20x%3D1.08%5Ctimes27%2B406%20%5C%5C%20x%3D435.16%20%5Cend%7Bgathered%7D)
Final Answer
Therefore , The heaviest 14% of fruits weigh more than 435.16 gms
Answer:
12
Step-by-step explanation:
12^2 is the greatest number that is closest to 148. then there is 4 as the smaller number 12-4=8
144+4=148
