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2 years ago

5

Concept of place value, ordering and rounding (in small and easy words)

1 answer:

Setler [38]2 years ago

6 0

Answer:

Place value is the value of each digit in a number. For example, the 5 in 350 represents 5 tens,When rounding an integer, all place values to the right of the rounding position are filled with zeros. For example, let's round 8,372 to the hundreds position, which currently contains the number 3. Because the number following the 3 is a 7, we raise the 3 to a 4, and the answer is 8,400.

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The volleyball team sold 16 items on the first day of a bake sale, 28 items on the second day, and 12 items on the last day. The

valina [46]

60 items were for sale because you need to add together the amounts that were sold plus what was left over, giving you everything that they had for sale.

6 0

2 years ago

Through: (3,3), parallel to y=8/3x+5

pshichka [43]

Answer:

(0,5)

Step-by-step explanation:

5 0

2 years ago

What is the measure of the other acute angle ?

Vaselesa [24]

Answer:

$62^{o}$

Step-by-step explanation:

All the angles in a triangle add up to $180^{o}$

Every right angle triangle has a right angle in it which is $90^{o}$

So to find the remaining angle, you do $180^{o}$ - $90^{o}$ - $28^{o}$ = $62^{o}$

7 0

2 years ago

Any one help please

zvonat [6]

Answer:

1: male + female $\leq$ 30

2: 140 + 25x $\geq$ 550

Step-by-step explanation:

8 0

2 years ago

1011+111 in binary form

Ann [662]

Answer:

10010

Step-by-step explanation:

$1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$111=1(2)^2+1(2)^1+1(2)^0$

So $1011+111$ gives us:

$1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$+$

$1(2)^2+1(2)^1+1(2)^0$

-----------------------------------------------------

Combine like terms:

$1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0$

$1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0$

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace $2^0$ with 1 and $2$ with $(2)^1$ :

$1(2)^3+1(2)^2+(2)^2+(2)^1(1)$

I want a $2^0$ number:

$1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0$

Combine like terms:

$1(2)^3+2(2)^2+1(2)^1+0(2)^0$

$2(2)^2=2^3$ :

$1(2)^3+2^3+1(2)^1+0(2)^0$

Combine like terms:

$2(2)^3+1(2)^1+0(2)^0$

We can rewrite the first term by law of exponents:

$2^4+1(2)^1+0(2)^0$

$1(2)^4+1(2)^1+0(2)^0$

So the binary form is:

$10010$

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

1 0 1 1

+ 1 1 1

------------------------------

(1) (1) (1)

1 0 1 1

+ 1 1 1

------------------------------

1 0 0 1 0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

8 0

3 years ago