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Harman [31]
3 years ago
5

Concept of place value, ordering and rounding (in small and easy words) ​

Mathematics
1 answer:
Setler [38]3 years ago
6 0

Answer:

Place value is the value of each digit in a number. For example, the 5 in 350 represents 5 tens,When rounding an integer, all place values to the right of the rounding position are filled with zeros. For example, let's round 8,372 to the hundreds position, which currently contains the number 3. Because the number following the 3 is a 7, we raise the 3 to a 4, and the answer is 8,400.

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Ksivusya [100]
I’m pretty sure this is right:

3 0
3 years ago
What is the sum of 3m + 7y + 5 - m - 6y?
nevsk [136]
3m + 7y + 5 + -1m + -6y = 0
Reorder the terms:5 + 3m + -1m + 7y + -6y = 0
Combine like terms: 3m + -1m = 2m5 + 2m + 7y + -6y = 0
Combine like terms: 7y + -6y = 1y5 + 2m + 1y = 0
Solving5 + 2m + 1y = 0
Solving for variable m'.
Move all terms containing m to the left, all other terms to the right.
Add '-5' to each side of the equation.5 + 2m + -5 + 1y = 0 + -5
Reorder the terms:5 + -5 + 2m + 1y = 0 + -5
Combine like terms: 5 + -5 = 00 + 2m + 1y = 0 + -52m + 1y = 0 + -5
Combine like terms: 0 + -5 = -52m + 1y = -5
Add '-1y' to each side of the equation.2m + 1y + -1y = -5 + -1y
Combine like terms: 1y + -1y = 02m + 0 = -5 + -1y2m = -5 + -1y
Divide each side by '2'.m = -2.5 + -0.5y
Roots  m=-2.5 + -0.5y

Simplify the following:3 m + 7 y + 5 - m - 6 y
Grouping like terms, 3 m + 7 y + 5 - m - 6 y = (7 y - 6 y) + (3 m - m) + 5:(7 y - 6 y) + (3 m - m) + 5
7 y - 6 y = y:y + (3 m - m) + 5
3 m - m = 2 m:Answer:  y + 2 m + 5
Not sure what you need so I gave you Simplification and Roots.


8 0
3 years ago
A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. In earlier stu
Elena L [17]

Answer:

75

Step-by-step explanation:

6 0
3 years ago
Help me asap thanks you.
liraira [26]
Ok i dont know the anwser but go to tiger algerbra and get the anwser there i hope you have a nice day
3 0
3 years ago
Negate the conditional statement.
Tpy6a [65]

(not <em>a</em> or not <em>b</em>) implies <em>c</em>   <==>   not (not <em>a</em> or not <em>b</em>) or <em>c</em>

so negating gives

not [(not <em>a</em> or not <em>b</em>) implies <em>c</em>]   <==>   not[ not (not <em>a</em> or not <em>b</em>) or <em>c</em>]

which we can simplify somewhat to

not (not (not <em>a</em> or not <em>b</em>)) and not <em>c</em>

(not <em>a</em> or not <em>b</em>) and not <em>c</em>

(not <em>a</em> and not <em>c</em>) or (not <em>b</em> and not <em>c</em>)

not (<em>a</em> or <em>c</em>) or not (<em>b</em> or <em>c</em>)

not ((<em>a</em> or <em>c</em>) and (<em>b</em> or <em>c</em>))

not ((<em>a</em> and <em>b</em>) or <em>c</em>)

3 0
3 years ago
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