Answer: compare the relative strength of coefficients.
Step-by-step explanation: The Coefficient of determination usually denoted as R^2 is obtained by taking the squared value of the correlation Coefficient (R). It's value ranges from 0 to 1 and the value obtained gives the proportion of variation in the dependent variable which could be attributed to it's correlation or relationship to th independent variable. With a R^2 value close to 1, this means a large portion of Variation in a variable A could be explained due to changes in variable B while a low value signifies a low variance between the variables. Hence, the Coefficient of determination is used in comparing the relative strength of the Coefficients in other to establish whether a weak or strong relationship exist.
Answer:
The amount of weight he has lost in 3 months is 1.215 stone or 1 stone 3 pounds
Step-by-step explanation:
From the above question, we are to calculate the amount of weight he has lost in three months
1 stone = 14 pounds
Let's convert all the weight lost to stone
At the start of the diet keirin weighted 14 stone 13 pounds
14 pounds = 1 stone
13 pounds = x
Cross Multiply
14x = 13
x = 13/14
x = 0.9285714286 stone
Approximately = 0.929 stone
Hence:
14 stone 13 pounds = 14 + 0.929 = 14.929 stone
Three months later he weighted 13 stone 10 pounds
14 pounds = 1 stone
10pounds = x
Cross Multiply
14x = 10
x = 10/14
x = 0.7142857143 stone
Approximately = 0.714 stone
Hence:
13 stone 10 pounds = 13 + 0.714 = 13.714 stone
The amount of weight he has lost is calculated as:
14.929 stone - 13.714 stone = 1.215 stone or 1 stone 3 pounds
Answer:
The rise is -5 the run is 4
Step-by-step explanation:
Slope (m) =
ΔY
ΔX
=
-5
4
=
-1.25
θ =
arctan(
ΔY
) + 360°
ΔX
=
308.65980825409°
ΔX = 2 – -2 = 4
ΔY = -1 – 4 = -5
Distance (d) = √ΔX2 + ΔY2 = √41 = 6.4031242374328
Equation of the line:
y = -1.25x + 1.5
or
y =
-
5
x
4
+
3
2
When x=0, y = 1.5
When y=0, x = 1.2
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