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WARRIOR [948]
3 years ago
5

Jerry works no more than 20 hours a week during the school year. He is paid $10 an hour for tutoring geometry students and $7 an

hour for delivering pizzas for Pizza King. He wants to spend at least 3 hours, but no more than 8 hours, a week tutoring. Find Jerry’s maximum weekly earnings.
Mathematics
1 answer:
zvonat [6]3 years ago
4 0
Works no more than 20 hours/week

3-8 hours tutoring
Subtract 3-8 from the 20 to give you hours for pizza delivery

So anywhere between 12-17 hours for pizza delivery

To find his maximum weekly hours (keeping in no more than 20 hours)

3 hours tutoring
17 hours pizza

3 x $7 = $. $21
17 x $10 = $170
-----------------------
$191
If he did
8 hours of tutoring
12 hours of pizza

8 x &7 = $56
12 x $10 = $120
------------------------
$176

So he'd be better off working more hours delivering pizza & less doing tutoring


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Step-by-step explanation:

Solution

According to remainder theorem, when f(x) is divided by (x+2), Remainder =f(−2)

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5 0
2 years ago
Im confusedd, please help??
spayn [35]

Answer:  three sets of value show 3 consecutive increases and they could be the intensities during fourth, fifth, and six visits:

  • 66%, 69%, 72%;
  • 63%, 65%, 67%, and
  • 67%, 72%, 77%

Explanation:


1) The program recommends a constant intensity for 3 visits, which is what the table shows:

Day        Intensisty

1             63%

2            equal ⇒ 63%

3            equal ⇒ 63%


2) Hence, you have to determine the valid sets that meet the recommendation for the fourth, fifth, and six visits, which are the next three.


2) For the next three visits, the program recommensd increasing intensities.


There are three options that show 3 consecutive increases; they are:

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Therefore, those are the choices that apply.

4 0
3 years ago
Help me out pls!!!!!!
klio [65]
It is at (2,4) hope it helps
4 0
2 years ago
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How to convert y = - 2\5 x to standard form
coldgirl [10]
Bring it to the form ax + by = c, where a is positive, and there are no fractions in the equation.
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2/5x + y = 0
Then multiply everything by 5 to get rid of the fraction
2x + 5y = 0 <==
5 0
3 years ago
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