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WARRIOR [948]
4 years ago
5

Jerry works no more than 20 hours a week during the school year. He is paid $10 an hour for tutoring geometry students and $7 an

hour for delivering pizzas for Pizza King. He wants to spend at least 3 hours, but no more than 8 hours, a week tutoring. Find Jerry’s maximum weekly earnings.
Mathematics
1 answer:
zvonat [6]4 years ago
4 0
Works no more than 20 hours/week

3-8 hours tutoring
Subtract 3-8 from the 20 to give you hours for pizza delivery

So anywhere between 12-17 hours for pizza delivery

To find his maximum weekly hours (keeping in no more than 20 hours)

3 hours tutoring
17 hours pizza

3 x $7 = $. $21
17 x $10 = $170
-----------------------
$191
If he did
8 hours of tutoring
12 hours of pizza

8 x &7 = $56
12 x $10 = $120
------------------------
$176

So he'd be better off working more hours delivering pizza & less doing tutoring


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saw5 [17]
1.0% exactly 0.9743. I hope I helped!
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The function y=ex is vertically stretched by a factor of 2, reflected across the x-axis, and then shifted down 3 units, find the
Anettt [7]

Answer:

y = - 2 e^{x} - 3

Step-by-step explanation:

We have to vertically stretch the function y = e^{x} by a factor of 2.

Then the function will become y = 2e^{x}.

Then it is reflected across the x-axis.

So, the new function will be y = - 2e^{x}.

Now, if the function is shifted down 3 units then the final function will become y = - 2 e^{x} - 3 (Answer)

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3 years ago
In June, Ryan sold twice as many newspaper subscriptions as George. In July, Ryan sold 5 fewer subscriptions than he did in June
ArbitrLikvidat [17]
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3 years ago
A random sample of math majors taking an introductory statistics course were surveyed after completing the final exam. They were
quester [9]

Answer:

E(X) =1 *\frac{1}{5} +2 *\frac{2}{5} +7*\frac{2}{5}= 3.8

Now we can find the second moment with this formula:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =1^2 *\frac{1}{5} +2^2 *\frac{2}{5} +7^2*\frac{2}{5}= 21.4

The variance would be given by:

Var(X) =E(X^2) -[E(X)]^2 = 21.4 -[3.8]^2 = 6.96

And the deviation would be:

Sd(X) =\sqrt{6.96}= 2.638

Step-by-step explanation:

For this case we have the following distribution given:

X      1      2      7

P(X) 1/5  2/5   2/5

We need to begin finding the mean with this formula:

E(X) = \sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(X) =1 *\frac{1}{5} +2 *\frac{2}{5} +7*\frac{2}{5}= 3.8

Now we can find the second moment with this formula:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =1^2 *\frac{1}{5} +2^2 *\frac{2}{5} +7^2*\frac{2}{5}= 21.4

The variance would be given by:

Var(X) =E(X^2) -[E(X)]^2 = 21.4 -[3.8]^2 = 6.96

And the deviation would be:

Sd(X) =\sqrt{6.96}= 2.638

7 0
3 years ago
Are these Equivalent expressions 4(2 + 3) and 4(2) + 4(3)
slava [35]

Answer:

Yes, they are equivalent.

Step-by-step explanation:

  1. To see if they're equivalent, you have to solve them. Start with the first one. Steps are below.
  2. Apply the distributed property: 8 + 12
  3. 8 + 12 = 20

For second expression:

  1. 4(2) = 4 × 2 = 8
  2. 4(3) = 4 × 3 = 12
  3. Put them together: 8 + 12
  4. 8 + 12 = 20

Making a conclusion:

Because they both have the same answer, they are equivalent expressions.

I hope this helps!

4 0
3 years ago
Read 2 more answers
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