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3 years ago

Finding the Slope of a Line from a Table

Mathematics

1 answer:

lakkis [162]3 years ago

3 0

Answer:

m = rise / run = 1/7

Step-by-step explanation:

Recall that the slope of a line is m = rise / run.

Here we look at x first (to calculate the run): x begins at -7 and ends at 0. Thus, the run is 0 - (-7), or 7.

Now look at how y behaves (find the rise): y begins at 0 and ends at 1. Thus, the rise is 1.

Therefore the slope of the line connecting the two poings given is

m = rise / run = 1/7

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Help MOI PLS!! :):):):):)

katrin [286]

Answer:

z=-1

Step-by-step explanation:

First combine the like terms: -4z-11z+2z-(-6z)=-4z-11z+2z+6z=-15z+8z=-7z

Then solve after combining like terms:

$\frac{-7z}{-7} =\frac{7}{-7}$

$z=-1$

6 0

3 years ago

Read 2 more answers

Find the area of the shaded region. Round your answer to the nearest hundredth.

PilotLPTM [1.2K]

Answer:

4.56

Step-by-step explanation:

i see a sector hosting 2 semi circles.

this sector area will be .25 of area of circle with radius 4ft.

area of sector = .25*π*16= 4π ft^2

area of semi circle of radius 2ft = .5π*4= 2πft^2

area of 2 semicircles = 4π

the total area of sector = area of 2 semicircles - intersection area + area not covered by semi circles

4π = 4π - intersection area+area not covered by semi circles

intersection area = area not covered by semi circles

now draw a square starting from the intersection point of 2 semi circles at their upper portion. the side will be 2ft

the area of intersection will be covered in the square.

area of intersection = 2*quarter area of circle of radius 2ft - area of square

= 2*(.25π4) - 4

2π-4 = 2.28

area of intersection = area not covered by semicircle

so area of shaded region = 4.56

4 0

2 years ago

Can someone delete my Question Like A MODERATOR

DochEvi [55]

Answer:

im not moderator

Step-by-step explanation:

dont post a question like this

8 0

2 years ago

A triangle with vertices A(0,0), B(6,0), and C(0,9) is rotated 360 about the y-axis. What is the volume of the figure?

Luden [163]

Given:

A triangle with vertices A(0,0), B(6,0), and C(0,9) is rotated 360 about the y-axis.

To find:

The volume of the figure.

Solution:

Points A(0,0) and C(0,9) lies on the y-axis. Length of AC is 9 units.

Points A(0,0) and B(6,0) lies on the x-axis. Length of AB is 6 units.

If a triangle with vertices A(0,0), B(6,0), and C(0,9) is rotated 360 about the y-axis, then it will form a cone with radius 6 units and height 9 units.

Volume of a cone is

$V=\dfrac{1}{3}\pi r^2h$

where, r is radius of the base and h is vertical height of the cone.

Putting r=6 and h=9, we get

$V=\dfrac{1}{3}\pi (6)^2(9)$

$V=\pi (36)(3)$

$V=108\pi$

Therefore, the volume of the figure is $108\pi$ sq. units.

7 0

3 years ago

PLEASE HURRY, thanks!

forsale [732]

The answer to the problem is C 2^12 the reason is because 16^3 is 4,096 and
2^7=128
2^11=2,048
2^12=4,096 which is what we want so this is the answer
2^64=18,447,744,073,709,551,616 which is not even close to what we want at all

So the answer is C 2^12

8 0

4 years ago

Read 2 more answers