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Gemiola [76]
3 years ago
11

Wendy's mother recorded how many donuts she has eaten over the past few months. Jelly-filled donuts 6 maple donuts 53 glazed don

uts 11 powdered sugar donuts 5 What is the experimental probability that the next donut Wendy eats will be a powdered sugar donut? Write your answer as a fraction or whole number. P(powdered sugar donut) =
Mathematics
1 answer:
coldgirl [10]3 years ago
3 0

Answer:

P(\text{Powdered sugar donut})=\dfrac{1}{15} .

Step-by-step explanation:

It is given that Wendy's mother recorded how many donuts she has eaten over the past few months.

Jelly-filled donuts = 6

Maple donuts = 53  

Glazed donuts = 11  

Powdered sugar donuts = 5

Now,

Total number of donuts = 6 + 53 + 11 + 5 = 75

We need to find the experimental probability that the next donut Wendy eats will be a powdered sugar donut.

P(\text{Powdered sugar donut})=\dfrac{\text{Powdered sugar donuts}}{\text{Total number of donuts}}

P(\text{Powdered sugar donut})=\dfrac{5}{75}

P(\text{Powdered sugar donut})=\dfrac{1}{15}

Therefore, P(\text{Powdered sugar donut})=\dfrac{1}{15}.

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The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.
andrezito [222]

Answer:

Given the equation: 3x^2+10x+c =0

A quadratic equation is in the form: ax^2+bx+c = 0 where a, b ,c are the coefficient and a≠0 then the solution is given by :

x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a} ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}

Simplify:

x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}

Also, it is given that the difference of two roots of the given equation is 4\frac{2}{3} = \frac{14}{3}

i.e,

x_1 -x_2 = \frac{14}{3}

Here,

x_1 = \frac{-10 + \sqrt{100- 12c}}{6} ,     ......[2]

x_2= \frac{-10 - \sqrt{100- 12c}}{6}       .....[3]

then;

\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}

simplify:

\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}

or

\sqrt{100- 12c} = 14

Squaring both sides we get;

100-12c = 196

Subtract 100 from both sides, we get

100-12c -100= 196-100

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve x_1 , x_2

x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}

or

x_1 = \frac{-10 + \sqrt{100- 96}}{6} or

x_1 = \frac{-10 + \sqrt{4}}{6}

Simplify:

x_1 = \frac{-4}{3}

Now, to solve for x_2 ;

x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}

or

x_2 = \frac{-10 - \sqrt{100- 96}}{6} or

x_2 = \frac{-10 - \sqrt{4}}{6}

Simplify:

x_2 = -2

therefore, the solution for the given equation is: -\frac{4}{3} and -2.


3 0
3 years ago
would you prefer to purchase a cheap car which cost more to operate or to purchase a expensive car which cost less to operate? w
alexandr402 [8]

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3 years ago
What is the answer to x²+12x+32
maxonik [38]

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amm1812

Answer:

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the answer is basically c.

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ale4655 [162]
Shorter <span>piece = x
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x + 4x = 48.5
5x = 48.5
x = 48.5/5
x = 9.7 cm   </span>←  shorter piece

longer piece = 4x = 4 * 9.7 = 38.8 cm
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