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RideAnS [48]
3 years ago
13

The data for 2019 and 2020 is 43.04 and 39.93 what is the percentage change?

Mathematics
1 answer:
NeTakaya3 years ago
6 0

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Hiiiiiii im soooooooo tired but i gotta clean my room lol
kumpel [21]

Answer:

lol

Step-by-step explanation:

3 0
3 years ago
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One pump can empty a pool in 4 days, whereas a second pump can empty the pool in 10 days. How long will it take the two pumps, w
gtnhenbr [62]

Answer:

20/7 days (just less than 3 days)

Step-by-step explanation:

Recall that (1 job) = (rate)(time), so time = (1 job) / (rate).

Set up and solve the following equation:

  1 job

------------------------------- = time required for 2 pumps working together

1 job         1 job

---------- + -------------

4 days      10 days

This comes out to:

              1 job

------------------------------------------- = time required

10 job-days      4 job-days

------------------ + -----------------

   40 days           40 days

or:

    1 job

-------------------- = (40/14) days, or 20/7 days (just less than 3 days)

14 job·days

-----------------

   40 days  

7 0
3 years ago
Do it quickly please for brainliest
Murrr4er [49]

Answer:

x = 98/17 = 5.765

Step-by-step explanation:

6 0
2 years ago
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Rectangle with side lengths of 1/2 ft. and 3/4 ft. What is the area and perimeter?
deff fn [24]
Perimeter: all the sides added together, so that would be 1/2+1/2+3/4+3/4, which is 2 and a half feet

Area: the two side lengths multiplied, so 1/2*3/4, which is 3/8 feet squared
4 0
3 years ago
Rate of change of rational functions
densk [106]

Answer:

0.635

Step-by-step explanation:

rate~of~change = \dfrac{f(x_2) - f(x1)}{x_2 - x_1}

rate~of~change = \dfrac{f(x_2) - f(x1)}{x_2 - x_1}

x_1 = 0       x_2 = 0.3

f(x) = \dfrac{-7x^3}{x^4 - 1}

f(x_1) = f(0) = \dfrac{-7(0)^3}{(0)^4 - 1}

f(x_1) = \dfrac{0}{-1} = 0

f(x_2) = f(0.3) = \dfrac{-7(0.3)^3}{(0.3)^4 - 1}

f(x_2) = \dfrac{-0.189}{-0.9919} = 0.190543

rate~of~change = \dfrac{0.190543 - 0}{0.3 - 0} = 0.635

5 0
3 years ago
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