Answer:
- the fraction of the turbine work output used to drive the compressor is 50%
- the thermal efficiency is 29.6%
Explanation:
given information:
= 300 k
= 700 kPa
= 580 K
Qin = 950 kj/kg
efficiency, η = 86% = 0.86
Assume, Ideal gas specific heat capacities of air, = 1.005
k = 1.4
(a) the fraction of the turbine work output used to drive the compressor
Qin = ( - )
- = Qin /
= Qin / +
thus,
= = 1525 K
= \
=
so,
= \
= \
= 1525 K
= 875 K
= ( - )
= 1.005 kj/kgK (580 K - 300 K)
= 281.4 kJ/kg
= η ( - )
= 0.86 (1.005 kj/kgK) (1525 k - 875 K)
= 562.2 kJ/kg
therefore,
the fraction of turbine =
=
= 50%
(b) the thermal efficiency
η = ΔW/
= ( - )/
= /950
= 29.6%
Answer:
k1 + k2
Explanation:
Spring 1 has spring constant k1
Spring 2 has spring constant k2
After being applied by the same force, it is clearly mentioned that spring are extended by the same amount i.e. extension of spring 1 is equal to extension of spring 2.
x1 = x2
Since the force exerted to each spring might be different, let's assume F1 for spring 1 and F2 for spring 2. Hence the equations of spring constant for both springs are
k1 = F1/x -> F1 =k1*x
k2 = F2/x -> F2 =k2*x
While F = F1 + F2
Substitute equation of F1 and F2 into the equation of sum of forces
F = F1 + F2
F = k1*x + k2*x
= x(k1 + k2)
Note that this is applicable because both spring have the same extension of x (I repeat, EXTENTION, not length of the spring)
Considering the general equation of spring forces (Hooke's Law) F = kx,
The effective spring constant for the system is k1 + k2
Answer:
The total distance is equal to the change in total position of the person, but the displacement of the person is zero.
Explanation:
- The distance is the total change in the positions of the toy robot. it is having only magnitude and it is a scalar quantity.
- The displacement is the difference between the final and initial position of the toy robot. it is a vector quantity having magnitude and direction
- Since the distance is the change in positions, so the magnitude of the distance will be equal to the up and down distance covered.
- If the toy robot travels in a straight line path and returns back to its original location, the magnitude of the distance and displacement doesn't depend on the speed of the toy robot.
Of my knowlaedge, the suns light rays are so intense that they bounce off of other planets and shine on the face of the moon giving us the ability ti see the moon at night.