A toy robot moved from a starting point, traveling in a straight line at different speeds and then turning around and returning
1 answer:
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Answer:
Explanation:
To find the angular velocity of the tank at which the bottom of the tank is exposed
From the information given:
At rest, the initial volume of the tank is:
where;
height h which is the height for the free surface in a rotating tank is expressed as:
at the bottom surface of the tank;
r = 0, h = 0
∴
0 = 0 + C
C = 0
Thus; the free surface height in a rotating tank is:
Now; the volume of the water when the tank is rotating is:
dV = 2π × r × h × dr
Taking the integral on both sides;
replacing the value of h in equation (2); we have:
Since the volume of the water when it is at rest and when the angular speed rotates at an angular speed is equal.
Then
Replacing equation (1) and (3)
Finally, the angular velocity of the tank at which the bottom of the tank is exposed = 10.48 rad/s
Answer:
F = 339.23 N
Explanation:
Weight of a car, W = 1050 N
Initial velocity, u = 0
Final velocity, v = 42 m/s
Time, t = 13 s
The weight of an object is given by :
W = mg
g is the acceleration due to gravity
The force acting on car is :
So, the force acting on the car is 339.23 N.