Answer:
see explaination for program code
Explanation:
scalar_product = 0
li=[]
li2=[]
#reading numbers1.txt and numbers2.txt intoli and li2 respectively
with open('numbers1.txt') as n1, open('numbers2.txt') as n2:
for line1 in n1:
li.append(int(line1))
for line2 in n2:
li2.append(int(line2))
#storing min list size into variable l
a=len(li)
b=len(li2)
if a<b:
l=a
else:
l=b
#calculating scalar product
for i in range(l):
scalar_product=scalar_product+li[i]*li2[i]
print("scalar product is",scalar_product)
Answer:
it would have to be flow control which would be C.
Explanation:
its the first one x 3/14 bc 2/7 times 3/4 makes 6/28. 6/28 simplified is 3/14
16235 to the nearest ten thousand would be 20,000.
Hope this helps :)
~ Davinia.
