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spin [16.1K]
3 years ago
12

The angle 01 is located in Quadrant I, and sin(01)=1/2 what is the value of cos(01)

Mathematics
1 answer:
vovikov84 [41]3 years ago
4 0

Answer:

The value of Cos(01) is 0.866 or √3/2

Step-by-step explanation:

In this question, we are asked to calculate the value of cos (01) given the value of sin(01)

Now, given the value of sin (01), we can calculate the value of cos (01).

To get the value of 01, we simply find the value of the arc sin 01

Mathematically since sin (01) = 1/2

(01) = arc sin (1/2)

(01) = 30 degrees

Now since 01 = 30 degrees

cos 01 = Cos (30) = 0.8666 or simply √3/2

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Answer:

2 I think

Step-by-step explanation:

6 0
3 years ago
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Given the trinomial, what is the value of the coefficient B in the factored form? 2x2 + 4xy − 48y2 = 2(x + By)(x − 4y) −12 12 −6
Sonja [21]

Answer:

B is 6.

Step-by-step explanation:

We are trying to find a value for B such that:

2x^2+4xy-48y^2=2(x+By)(x-4y) is true for every x,y.

So let's choose x=0,y=1:

2(0)^2+4(0)(1)-48(1)^2=2(0+B(1))(0-4(1))

2(0)+0-48=2(B)(-4)

0-48=-8B

-48=-8B

Divide both sides by -8:

\frac{-48}{-8}=B

6=B

B=6

Note: I didn't want to choose y to be 0 because the value of B would disappear from the equation. So you should be able to have chosen any x and y except for y=0 to solve the equation for B.

Check:

So let's check and use foil to multiply out the right hand side.

(x+6y)(x-4y)

x(x)+x(-4y)+6y(x)+6y(-4y)

x^2-4xy+6xy-24y^2

x^2+2xy-24y^2

There was a 2 in front of that multplicapltiation:

2(x+6y)(x-4y)

2(x^2+2xy-24y^2)

2x^2+4xy-48y^2

This is exactly what we have on the left hand side of your given equation.

3 0
3 years ago
5) dilation of 2 about the origin
Misha Larkins [42]

Answer:

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5 0
3 years ago
What function is increasing? will give brainlist !
Wewaii [24]

Answer:

Option B.

Step-by-step explanation:

Option A.

f(x) = (0.5)^{x}

Derivative of the given function,

f'(x) = \frac{d}{dx}(0.5)^x

      = (0.5)^x[\text{ln}(0.5)]

      = -(0.693)(0.5)^{x}

Since derivative of the function is negative, the given function is decreasing.

Option B. f(x) = 5^x

f'(x) = \frac{d}{dx}(5)^x

      = (5)^x[\text{ln}(5)]

      = 1.609(5)^x

Since derivative is positive, given function is increasing.

Option C. f(x) = (\frac{1}{5})^x

f'(x) = \frac{d}{dx}(\frac{1}{5})^x

      = \frac{d}{dx}(5)^{(-x)}

      = -5^{-x}.\text{ln}(5)

Since derivative is negative, given function is decreasing.

Option D. f(x) = (\frac{1}{15})^x

                f'(x) = -15^{-x}[\text{ln}(15)]

                       = -2.708(15)^{-x}

Since derivative is negative, given function is decreasing.

Option (B) is the answer.

7 0
3 years ago
ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions
stiv31 [10]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
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