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never [62]
3 years ago
14

How many solutions does 7x -10 = 7(x+3)

Mathematics
1 answer:
inessss [21]3 years ago
4 0

Answer: The answer to this question is that there is no solution to that problem

Step-by-step explanation:

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Solve each equation.Show your work.<br>Can someone help me please??​
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Answer:

1/2a = -5

a = (-5 x 2) : 1

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b = 8 - 9,5

b = -1,25

0,1 = -10c

c = 0,1 : -10

c = -0,01

I hope it's helpful.

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Step-by-step explanation:

\text{Let}\ A(x_1,\ y_1)\ \text{and}\ B(x_2,\ y_2).\ \text{Then the distance between}\ A\ \text{and}\ B\ \text{is:}\\\\|AB|=\sqrt{(x_2-x_1)^2+(y_2-y1)^2}\\\\Example:\\\\A(2,\ 5),\ B(-1,\ 1)\\\\|AB|=\sqrt{(-1-2)^2+(1-5)^2}=\sqrt{(-3)^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5

7 0
3 years ago
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A small business earns a profit of $6500 in January and $17,500 in May. What is the rate of change in profit for this time perio
MAXImum [283]

Rate of change of profit for this period is $2750 per month

<em><u>Solution:</u></em>

Given that,

Profit of $6500 in January and $17,500 in May

<em><u>To find: Rate of change</u></em>

Since,

January is the first month of the year (1) while May is the fifth month (5)

<em><u>Therefore, we get two points</u></em>

(1, 6500) and (5, 17500)

Using these points we can find the rate of change in profit for this time period

<em><u>The rate of change using the following formula:</u></em>

m = \frac{y_2-y_1}{x_2-x_1}

Here from the points,

(x_1, y_1) = (1, 6500)\\\\(x_2, y_2) = (5, 17500)

<em><u>Therefore, rate of change is given as:</u></em>

m = \frac{17500-6500}{5-1}\\\\m = \frac{11000}{4}\\\\m = 2750

Thus rate of change of profit for this period = $2750 per month

8 0
3 years ago
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